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Orthogonal coordinates diagonalize a finite-dimensional Gaussian noise law

Statement

Assume AC. Let K∈Rd×d be symmetric positive definite and let Z∼Nd(0,K) be the additive noise in Finite-dimensional additive Gaussian channel with average power. Then there are an orthogonal matrix U and positive numbers λ1,…,λd such that K=UTdiag⁡(λ1,…,λd)U and the coordinates of UZ are independent with laws N(0,λj). For every input X, ∥UX∥2=∥X∥2 and U(X+Z)=UX+UZ, so this change of coordinates preserves the power constraint and the channel law.

Facts & Assumptions

Given: AC, a positive-definite covariance matrix K, and a centered Gaussian vector Z with covariance K.

[A1]

The Axiom of Choice: AC is assumed by the multivariate-normal construction and by the orthogonal-normal invariance supplier.

[F1]

Real spectral theorem: a self-adjoint endomorphism of a finite-dimensional real inner product space has an orthonormal eigenbasis: a real symmetric endomorphism has an orthonormal eigenbasis; positive definiteness makes each eigenvalue positive.

[F2]

A non-negative operator has a unique non-negative square root: a positive-semidefinite symmetric matrix has a unique positive-semidefinite square root.

[F3]

Multivariate normal law, including singular covariance and Standard normal and normal laws: Nd(0,K) is realized as K1/2G with independent standard-normal coordinates in G.

[F4]

Orthogonal transformations preserve the standard normal product law: under AC, if G∼Nd(0,Id) has independent standard-normal coordinates and UTU=Id, then UG again has independent standard-normal coordinates.

Proof

1.1F1F2givenchoose

By [F1], choose an orthogonal eigenbasis U for K, so K=UTΛU with Λ=diag⁡(λ1,…,λd) and λj>0. The positive square root is K1/2=UTΛ1/2U: this matrix is positive semidefinite, squares to K, and is therefore the unique square root in [F2].

2.1A1F3F4step 1.1algebra

By [F3], write Z in law as K1/2G. Since UUT=Id, UZ therefore has the law of Λ1/2UG. By [A1] and [F4], the coordinates of UG are independent standard normals; multiplication by λj gives independent N(0,λj) coordinates.

3.1step 1.1step 2.1algebra∎

Orthogonality gives ∥UX∥22=XTUTUX=∥X∥22, and linearity gives U(X+Z)=UX+UZ. Thus the transformed channel has parallel independent Gaussian noise and exactly the same input power and code/error correspondence.

Depends on

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