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Height in a quotient measures chains between two primes
Statement
Let be a commutative ring and let be prime ideals. Then the height of in is the supremum of the lengths of strict prime chains
in .
Facts & Assumptions
Given: A commutative ring and prime ideals .
Prime ideals of correspond exactly to the prime ideals of containing , with strict inclusions preserved (Prime ideals of a quotient ring are exactly the prime ideals containing the ideal).
Height is the supremum of the lengths of strict prime chains ending at the chosen prime (Height equals local dimension).
Proof
By [L1], strict prime chains in ending at are in bijection with strict prime chains in beginning at and ending at . Corresponding chains have the same length.
Applying [L2] to the prime of the quotient ring , the height of is exactly the supremum of the lengths of those quotient chains. Step 1.1 translates that supremum into the displayed chains in .
Therefore height in the quotient is the relative chain length from to .
Depends on
Used by
Dependency tree · two levels
7 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- J. S. Milne, A Primer of Commutative Algebra, v4.03, §21 (standard reference, not scraped)
- The Stacks Project, Section 10.60: Dimension (standard reference, not scraped)