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Bounded variation controls adjacent Hermite–Genocchi windows

Statement

Let n≥1, let 0≤d<n, let x0<⋯<xn be real nodes, and fix a real query point x∈[x0,xn] distinct from the nodes. Let f∈Cd+1([x0,xn]), put g=f(d+1), and suppose g has finite total variation V=Var⁡[x0,xn](g) as defined in Bounded variation and total variation on an interval. For 0≤i≤n−d, put Gi=f[xi,…,xi+d,x]. Then ∑i=0n−d−1∣Gi+1−Gi∣≤V(d+1)!.

Facts & Assumptions

Given: n≥1, 0≤d<n, ordered real nodes x0<⋯<xn, a distinct query point x in their interval, f∈Cd+1, and Var⁡(f(d+1))=V<∞.

[F1]

Hermite–Genocchi simplex formula for divided differences: an order-(d+1) divided difference is the integral of f(d+1) over the standard simplex, whose volume is 1/(d+1)!.

[F2]

Bounded variation and total variation on an interval: V is the supremum, over finite partitions of the interval, of the sums of absolute successive increments of g.

[F3]

Higher derivatives and the classes Ck and C∞: Cd+1 means that the derivatives through order d+1 exist and are continuous on the closed interval.

[F4]

The natural numbers N (von Neumann): N contains 0 and is closed under successor, so d+1∈N.

Proof

1.1givenF1F3F4construct

By [F4], d+1∈N, so apply [F1] to each Gi, using the same simplex coordinates for each window and using the final coordinate for the fixed point x. Thus Gi=∫Δd+1g(yi(u)) du,yi(u)=uxx+∑k=0dukxi+k, where all coefficients are nonnegative and sum to one. By [F3], g is continuous on the closed interval. Therefore every yi(u) lies in [x0,xn].

2.1givenF1F2step 1.1algebra∎

For each fixed u, the sequence y0(u),y1(u),…,yn−d(u) is nondecreasing: each summand xi+k is nondecreasing in i and has coefficient uk≥0. Remove repeated values from this finite sequence and insert the interval endpoints; the definition [F2] then gives ∑i=0n−d−1∣g(yi+1(u))−g(yi(u))∣≤V. Using [F1], the triangle inequality for integrals, and this pointwise bound, ∑i∣Gi+1−Gi∣≤∫Δd+1∑i∣g(yi+1(u))−g(yi(u))∣ du≤V vol⁡(Δd+1)=V(d+1)!. This is the claimed total variation bound.

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