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The free right-right Hopf module on a vector space

Statement

Let k be a field, H a Hopf algebra over k, and V any k-vector space. On V⊗H define

(v⊗h)g:=v⊗hg,ρ(v⊗h):=∑(v⊗h1)⊗h2.

These maps make V⊗H a right-right Hopf module. No finite-dimensionality or choice of basis for V is needed.

Facts & Assumptions

Given: A field k, a Hopf algebra H over k, and a k-vector space V.

[F1]

A bialgebra has a unital associative algebra structure and a counital coassociative coalgebra structure (Bialgebras and bialgebra maps).

[F2]

The coproduct and counit are unital algebra homomorphisms, so Δ(hg)=∑h1g1⊗h2g2 (Bialgebras and bialgebra maps).

[F3]

Tensor products are algebraic; their elements are finite sums of elementary tensors and multilinear formulas define linear maps on them (Scalars, tensor powers, the empty tensor, opposite algebras and finite sums).

[F4]

A right-right Hopf module is a right module and right comodule satisfying ρ(xg)=∑x0g1⊗x1g2 (Right-right Hopf modules and coinvariants).

Proof

1.1givenF1F3construct

For each g∈H, the formula (v⊗h)g=v⊗hg extends linearly to V⊗H, since multiplication by g is linear in h; it is bilinear in (v⊗h,g). Associativity of H gives ((v⊗h)g)t=v⊗(hg)t=v⊗h(gt)=(v⊗h)(gt), and its unit gives (v⊗h)1H=v⊗h. Thus it is a right module action.

1.2givenF1F3

The formula ρ=id⁡V⊗Δ is linear. Coassociativity of Δ gives (ρ⊗id⁡)ρ(v⊗h)=∑(v⊗h1)⊗h2⊗h3=(id⁡⊗Δ)ρ(v⊗h), and the counit equation gives (id⁡V⊗H⊗ε)ρ(v⊗h)=∑v⊗h1ε(h2)=v⊗h under the tensor-unit identification. Hence ρ is a right coaction.

2.1givenF2F4step 1.1step 1.2algebra

For v⊗h and g∈H, multiplicativity of Δ gives ρ((v⊗h)g)=∑(v⊗h1g1)⊗h2g2. On the other side, ∑(v⊗h)0g1⊗(v⊗h)1g2=∑((v⊗h1)g1)⊗h2g2, which is the same tensor by the action definition. Thus the compatibility in [F4] holds on elementary tensors.

3.1step 2.1F3algebra∎

Both compatibility sides are linear in the V⊗H input and in g, and elementary tensors span the tensor product by [F3]. Therefore the equality of step 2.1 holds for every element, proving the Hopf-module compatibility.

Depends on

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Sources