How statement and proof provenance work
The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.
- Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
- AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
- AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.
These labels describe origin, not correctness: citations and verification chips remain separate evidence.
The free right-right Hopf module on a vector space
Statement
Let be a field, a Hopf algebra over , and any -vector space. On define
These maps make a right-right Hopf module. No finite-dimensionality or choice of basis for is needed.
Facts & Assumptions
Given: A field , a Hopf algebra over , and a -vector space .
A bialgebra has a unital associative algebra structure and a counital coassociative coalgebra structure (Bialgebras and bialgebra maps).
The coproduct and counit are unital algebra homomorphisms, so (Bialgebras and bialgebra maps).
Tensor products are algebraic; their elements are finite sums of elementary tensors and multilinear formulas define linear maps on them (Scalars, tensor powers, the empty tensor, opposite algebras and finite sums).
A right-right Hopf module is a right module and right comodule satisfying (Right-right Hopf modules and coinvariants).
Proof
For each , the formula extends linearly to , since multiplication by is linear in ; it is bilinear in . Associativity of gives , and its unit gives . Thus it is a right module action.
The formula is linear. Coassociativity of gives , and the counit equation gives under the tensor-unit identification. Hence is a right coaction.
For and , multiplicativity of gives . On the other side, , which is the same tensor by the action definition. Thus the compatibility in [F4] holds on elementary tensors.
Both compatibility sides are linear in the input and in , and elementary tensors span the tensor product by [F3]. Therefore the equality of step 2.1 holds for every element, proving the Hopf-module compatibility.
Depends on
Used by
Dependency tree · two levels
17 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Hans-Juergen Schneider, Lectures on Hopf Algebras, notes by Sonia Natale, Trabajos de Matematica 31/95 (standard reference, not scraped)
- D. S. Drogalski, Chapter 3: Hopf Algebras, UC San Diego 207A lecture notes (standard reference, not scraped)