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Homogeneous dual-basis sums: basis independence and weightwise finiteness

Statement

Let ν∈Q+, let (ua) be a field basis of Uq+[ν] and (va) its D-dual basis in Uq−[−ν] with respect to the normalized Drinfeld pairing of The Drinfeld pairing is nondegenerate in each root degree and matches the shuffle pairing (so D(ua,vb)=δab), and set Θν:=∑aua⊗va∈Uq+[ν]⊗Uq−[−ν]⊆C^, the ambient root-height completion of The root-height completion for weightwise quasi-R intertwiners. Then Θν is independent of the chosen basis of Uq+[ν], and Θ0=1⊗1. The family (Θν)ν has finite-dimensional homogeneous components and defines a vectorwise finite action under the exact finiteness hypotheses of the completion definition. Its degree-ν action shifts a label pair (μ,η) to (μ+ν,η−ν), preserving the total weight, and on finite-weight-space Oint pairs every fixed total-weight space has a uniform finite tail bound beyond which all components act as 0. No integral algebra coefficients are asserted, and the positive-height components have no same-weight-pair diagonal term.

Facts & Assumptions

Given: The graded Serre halves Uq±=⨁νUq±[±ν], the perfect normalized pairing D, and the completion C^=∏ν∈Q+Uq+[ν]⊗Uq−[−ν].

[F1]

Perfect graded pairing (The Drinfeld pairing is nondegenerate in each root degree and matches the shuffle pairing): D is homogeneous and perfect on every finite root degree, so each finite-dimensional Uq+[ν] has a unique D-dual basis in Uq−[−ν] and vice versa.

[F2]

Completion and finiteness (The root-height completion for weightwise quasi-R intertwiners): C^ is the diagonal root-height completion with root-degree convolution multiplication (AB)ν=∑β+γ=νAβBγ, each component sum being finite; a family acts on mμ⊗nη by its finite sum whenever Uq+[ν]mμ⊗Uq−[−ν]nη=0 for all sufficiently large ν; this holds for finite-union bounded-above first supports, for lowest second factors with bounded-below support, and uniformly on each fixed total-weight space of a pair of finite-weight-space Oint modules.

[F3]

Sample weights: Uq+[ν] acts on weight μ vectors by shifting to μ+ν and Uq−[−ν] acts on weight η vectors by shifting to η−ν; the tensor orientation is positive first, negative second.

Proof

technique · direct
1.1F1algebra

Basis independence. If ua′=∑bubgba for an invertible matrix g, then the dual basis is v′a=∑b(g−1)abvb, since ∑bgbc(g−1)ab=δac. Consequently ∑aua′⊗v′a=∑b,cub⊗vc∑agba(g−1)ac=∑bub⊗vb.

2.1F1F3step 1.1

Components and degree shift. By [F1] the pieces Uq±[±ν] are finite-dimensional, so each Θν lies in the finite-dimensional tensor product Uq+[ν]⊗Uq−[−ν] and Θ0=1⊗1; by [F3] the degree-ν action shifts (μ,η) to (μ+ν,η−ν) and preserves the total weight μ+η.

3.1F2step 2.1

Vectorwise finiteness and the uniform tail bound. The action on a vector mμ⊗nη is the sum of the finitely many terms with Uq+[ν]mμ≠0 and Uq−[−ν]nη≠0, and [F2] provides exactly the hypotheses under which this set of ν is finite and uniformly bounded on each fixed total-weight space of finite-weight-space Oint pairs. Hence the family defines a vectorwise finite action, and no integrality of coefficients or diagonal same-weight term is produced.

4.1step 1.1step 2.1step 3.1∎

Conclusion. Steps 1.1 and 2.1 give the stated basis independence, Θ0=1, finite-dimensional components and degree shift, and step 3.1 gives the exact finiteness scope; no integral algebra coefficient property is asserted.

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