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Elementary properties of the homogenized ideal
Statement
Let be a marked ideal of maximal order with and let be its homogenization (The homogenized ideal of a marked ideal of maximal order). Then: (1) if then ; (2) agrees with its truncation at order as an element of the equivalence class of ; (3) Assume AC. Then up to marked equivalence for the operation of Addition and multiplication of marked ideals; (4) if and has characteristic zero or perfect characteristic , then ; (5) .
Facts & Assumptions
Given: A marked ideal of maximal order with , with and homogenization .
Derivative ideals of an ideal sheaf and of a marked ideal: , , and for .
Marked ideals of maximal order, tangent directions and transversality to the exceptional divisors: in characteristic zero or perfect characteristic , maximal order implies . In every characteristic is an ideal subsheaf of .
Addition and multiplication of marked ideals: sums and products of marked ideals and their controlled transforms are computed componentwise as in that item.
The Axiom of Choice: AC is used in clause (3) through the iterated marked-sum theorem in [F4].
Proof
Clauses (1) and (2). If then and the defining sum has the single term , so , which is (1). For (2), extend the defining sum to all . For each , the -th term is contained in because , and hence is contained in . Since , the term is exactly . Thus every later term is contained in the last retained term, and the full sum equals its truncation.
Clause (5). For a local product generator of a summand , applying a coordinate derivative of total order at most gives sums of products with derivatives on the first factor and derivatives on the tangent factors, where . The first factor lies in . If , this is contained in because derivative ideals increase with their index. If , then , so at least one tangent factor is undifferentiated and the product contains a factor of . In both cases the resulting product lies in , proving . The reverse inclusion follows from and monotonicity of derivative ideals. Thus , proving (5).
Clause (3). Each product has underlying ideal and mark . Their literal ideal sum is with mark . Its support is the intersection of the supports of , since the order of an ideal sum is the minimum of the summand orders. At a common admissible center the controlled transform of the literal sum distributes termwise, because all marks are . Induction therefore identifies its test sequences and induced supports with the simultaneous ones for the summands. Under AC, [F4] gives exactly those supports and test sequences for the iterated marked sum. Thus the displayed operation represents up to marked equivalence, proving (3); no literal equality between a sum of ideal powers and a power of an ideal sum is used.
Clause (4). Assume and has characteristic zero or perfect characteristic . The maximal-order criterion in [F3] gives , so is maximal order and . Leibniz gives Since , the second sum is the sum of the terms for . In the first sum, the terms with are precisely the terms of after setting ; its remaining top term is , already the term of the second sum. The second sum itself consists of the terms of . Hence the derivative ideal is contained in that homogenized ideal, proving (4).
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