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Invariants of the hyperbolic action of the multiplicative group on the plane

Statement

Let Gm=C× act on C2 by t⋅(x,y)=(tx,t−1y) (Classical complex affine algebraic actions and rational modules). Then the invariant subring of C[x,y] (The coordinate ring of a classical affine algebraic set) is C[x,y]Gm=C[xy], a polynomial ring in one variable; explicitly, a polynomial f=∑a,bcabxayb is invariant if and only if cab=0 for every pair with a≠b (Monomials, coefficients, degree in each variable and total degree in F[x1,…,xn]).

Facts & Assumptions

Given: the multiplicative group Gm=C× acting on C2 by t⋅(x,y)=(tx,t−1y), and a polynomial f=∑a,bcabxayb∈C[x,y] written in its unique finite monomial expansion.

[F1]

The action and the action on functions. The map t⋅(x,y)=(tx,t−1y) is an algebraic action of Gm on the affine plane, and the induced left action on functions is (t⋅f)(p)=f(t−1⋅p), so that (t⋅f)(x,y)=f(t−1x,ty) (Classical complex affine algebraic actions and rational modules).

[F2]

Unique monomial expansion. Every polynomial in F[x1,…,xn] has a unique finite expansion f=∑tctxt over finitely many multi-indices; in particular the monomials are linearly independent over F and a polynomial is zero exactly when all its coefficients vanish (Monomials, coefficients, degree in each variable and total degree in F[x1,…,xn]).

[F3]

The coordinate ring of the plane. For an affine algebraic set X⊆kn the coordinate ring is k[X]=k[x1,…,xn]/I(X); for X=C2 this is C[x,y], with x and y the coordinate functions (The coordinate ring of a classical affine algebraic set).

Proof

technique · direct
1.1F1

For t∈Gm and a monomial xayb the function action of [F1] gives (t⋅(xayb))(x,y)=(t−1x)a(ty)b=tb−axayb, so the multiplicative group acts on each monomial by the scalar tb−a: monomials on the diagonal a=b are fixed, while off-diagonal monomials are scaled by a nonconstant character.

2.1F1F2step 1.1

An element f=∑a,bcabxayb∈C[x,y] is invariant under Gm if and only if ∑a,bcab(tb−a−1)xayb=0 for every t∈Gm; by step 1.1 this is the difference between t⋅f and f, and by uniqueness of the monomial expansion it holds if and only if cabtb−a=cab for all pairs (a,b) and all t∈Gm.

3.1F2step 2.1

The coefficient conditions hold if and only if cab=0 for every pair with a≠b. If f is invariant, fix a pair with a≠b; evaluating the condition of step 2.1 at the nonzero complex number t=2 gives cab(2b−a−1)=0, and 2b−a≠1 because 2b−a>1 for b>a and 0<2b−a<1 for b<a; hence cab=0. Conversely, if cab=0 whenever a≠b, then f=∑acaxaya is a sum of diagonal monomials, and by step 1.1 each such monomial satisfies t⋅(xaya)=ta−axaya=xaya, so t⋅f=f for every t and f is invariant.

4.1F2F3step 3.1∎

Consequently a polynomial f∈C[x,y] is Gm-invariant if and only if its expansion has no off-diagonal terms, that is, if and only if f=∑acaxaya lies in the subalgebra C[xy] generated by the invariant function xy. Hence C[x,y]Gm=C[xy]. The substitution φ:C[z]→C[x,y], z↦xy, is injective: if φ(g)=0 for g=∑ndnzn, then ∑ndnxnyn=0, and uniqueness of the monomial expansion forces every dn=0, so g=0. Therefore C[xy]≅C[z] is a polynomial ring in one variable, and the plane's invariant ring is C[xy].

Remarks

  • This is the invariant computation behind Brion's Example 1.27(2): the quotient of C2 by the hyperbolic Gm-action is the affine line with coordinate xy. The companion example uses exactly this lemma to identify the invariant ring with C[xy] and to describe the quotient map (x,y)↦xy; that the raw level set {xy=0} contains both the origin and the two coordinate axes is the phenomenon behind the stable-locus analysis there.
  • No choice is used: a single test value t=2 already separates every off-diagonal monomial from the invariant ones, so no infinite family of excluded values has to be avoided.

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