Alphabeta Math
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Conditional typical-set fan cardinality bound

Statement

Let P be the joint law of a finite-alphabet IID k-source on X=∏i=1kXi, and fix nonempty S⊆[k]. Put C=Sc and m:=∣X∣. For every η>0 there is δ>0 such that, for every n≥1, every fixed xCn∈XCn, and every ϵ>0, ∣{xSn:(xSn,xCn)∈Tn(P,δ,ϵ)}∣≤(n+1)mexp⁡ ⁣(n(HP(XS∣XC)+η)).

Facts & Assumptions

Given: The finite source law P, the fixed nonempty subset S, and η>0.

[F1]

Jointly typical blocks for a finite IID multisource: every block in Tn(P,δ,ϵ) has an empirical joint type q with ∥q−P∥∞≤δ; its additional information conditions only restrict membership further.

[F2]

Empirical types, n-types, and type classes: an attainable joint type is determined by its integer symbol counts, and its type classes are the fibers of the empirical-type map.

[F3]

Conditional type-class cardinality bound: for fixed xCn and a feasible joint type q, the number of compatible xSn is at most exp⁡(nHq(XS∣XC)).

[F4]

Continuity of finite conditional entropy in the joint law: q↦Hq(XS∣XC) is continuous at the fixed joint law P.

[F5]

Finite conditional entropy: conditional entropy is the finite weighted sum of conditional-law entropies, with zero-mass conditioning values omitted.

[F6]

Finite distributions, entropy, divergence, and stochastic matrices: finite entropy uses natural logarithms and 0ln⁡0=0.

Proof

1.1F1F4choose

By [F4], choose δ>0 so that every joint probability vector q with ∥q−P∥∞≤δ satisfies ∣Hq(XS∣XC)−HP(XS∣XC)∣≤η. The joint alphabet is identified with XS×XC by a coordinate permutation, so the same coordinatewise neighborhood applies to the joint type of (xSn,xCn).

1.2F2algebra

For the fixed xCn, each xSn in the set has a unique joint empirical type q by [F2]. There are at most (n+1)m possible such types, since each of the m joint symbol counts is an integer from 0 to n; the sum constraint can only reduce this count.

2.1F1F3F5F6step 1.1step 1.2algebra∎

For each feasible type q arising from a typical block, [F1] and step 1.1 give Hq(XS∣XC)≤HP(XS∣XC)+η. By [F3], its conditional type class has size at most exp⁡(n(HP(XS∣XC)+η)). Summing this bound over the at most (n+1)m types from step 1.2 proves the claimed inequality. The empty-complement case uses its singleton alphabet and the same count.

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