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Composition factors of the BGG kernel lie above the degree (BGG 10.6a)
Statement
Assume the Axiom of Choice (The Axiom of Choice). Let , let , and let be the BGG differential of The BGG differential from signed Verma maps (with the augmentation). Assume that the complex is exact in degrees , that is, for ; this hypothesis is vacuous for . If a simple module occurs in a composition series of , then with . Equivalently, no composition factor of has the form with .
Facts & Assumptions
Given: The Axiom of Choice, a dominant integral weight , an integer , the BGG complex with differentials , and the hypothesis that is exact in degrees .
The weak BGG resolution: is an exact complex of objects of and with each weight occurring once (Weak BGG resolution, Type of a module with a Verma filtration).
is a direct sum of Verma modules and is Verma-filtered with type , so the multiset of Jordan-Holder factors is : the factors of a direct sum and of a filtration are the multiset unions of the factors of the pieces, and the factors of are independent of the filtration (The BGG differential from signed Verma maps, The Bruhat graph and the BGG Verma sum in degree k, Composition series and composition factors of an object).
If a simple module occurs in a composition series of , then with in Bruhat order, so ; every composition factor of therefore has the form with (Jordan-Holder factors of Verma modules dominate the head (BGG 8.12)).
For a short exact sequence of objects of the multisets satisfy ; hence equalities of two of the multisets force the equality of the third, and for a subobject . Objects of have finite length and is abelian (Category O is abelian and extension closed among weight modules, Every object of O has finite length, Composition series and composition factors of an object).
The complex is exact at every degree (it is a resolution), while is a complex; by hypothesis it is exact at degrees (Weak BGG resolution, The BGG differential from signed Verma maps, Chain complex in an abelian category).
Proof
The comparison chain. We prove for all by induction on . Base : the augmentation is the same simple module, so , and [F2] gives ; by the additivity of [F4] applied to and to the same sequence for , the equality of the middle and quotient multisets gives .
Induction step. Let and assume . By exactness of at we have , and by the hypothesis of the statement (which covers ) we have ; hence . The first isomorphism theorem applied in the abelian category gives and , so . Since by [F2], additivity [F4] applied to the two short exact sequences and yields .
At , the comparison gives . Exactness gives . Applying [F4] to yields .
By [F2] , and by [F3] every simple factor in this union is with . Hence every composition factor of is of the form with , which proves the main assertion.
For the equivalent formulation, note first that , so every factor of is a factor of and hence, by [F3], of the form with . Given step 4.1, the condition "no factor of has the form with " is therefore equivalent to the main assertion.
Depends on
- The BGG differential from signed Verma maps
- Weak BGG resolution
- Jordan-Holder factors of Verma modules dominate the head (BGG 8.12)
- Composition series and composition factors of an object
- Every object of O has finite length
- Category O is abelian and extension closed among weight modules
- The Axiom of Choice
- Type of a module with a Verma filtration
- Verma modules
- The Bruhat graph and the BGG Verma sum in degree k
- Chain complex in an abelian category
Used by
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Sources
- Fan Zhou, The classical and the functorial BGG resolutions (Columbia thesis 2021), Part I Sec. 4.2.2 (BGG Lemma 10.6a), pp. 22-25 (standard reference, not scraped)
- A. Rocha-Caridi, Splitting criteria for modules induced from a subalgebra of a semisimple Lie algebra, Trans. AMS 262 (1980), Sec. 9 and Sec. 10, pp. 349-354 (standard reference, not scraped)