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Composition factors of the BGG kernel lie above the degree (BGG 10.6a)

Statement

Assume the Axiom of Choice (The Axiom of Choice). Let λ∈Λ+, let k≥0, and let dk ⁣:Ck(λ)→Ck−1(λ) be the BGG differential of The BGG differential from signed Verma maps (with d0=π the augmentation). Assume that the complex C∙(λ) is exact in degrees 0,…,k−1, that is, im⁡dj+1=ker⁡dj for 0≤j≤k−1; this hypothesis is vacuous for k=0. If a simple module L(μ) occurs in a composition series of ker⁡dk, then μ=u∘λ with ℓ(u)≥k+1. Equivalently, no composition factor of ker⁡dk has the form L(u∘λ) with ℓ(u)≤k.

Facts & Assumptions

Given: The Axiom of Choice, a dominant integral weight λ∈Λ+, an integer k≥0, the BGG complex C∙(λ) with differentials dj, and the hypothesis that C∙(λ) is exact in degrees 0,…,k−1.

[F1]

The weak BGG resolution: 0→B∣Φ+∣(λ)→⋯→B1(λ)→B0(λ)→Πλ→0 is an exact complex of objects of O and Typ⁡Bi(λ)={w∘λ:ℓ(w)=i} with each weight occurring once (Weak BGG resolution, Type of a module with a Verma filtration).

[F2]

Ci(λ)=⨁ℓ(w)=iM(w∘λ) is a direct sum of Verma modules and Bi(λ) is Verma-filtered with type {w∘λ:ℓ(w)=i}, so the multiset of Jordan-Holder factors is JH⁡Ci=⨆ℓ(w)=iJH⁡M(w∘λ)=JH⁡Bi: the factors of a direct sum and of a filtration are the multiset unions of the factors of the pieces, and the factors of M(w∘λ) are independent of the filtration (The BGG differential from signed Verma maps, The Bruhat graph and the BGG Verma sum in degree k, Composition series and composition factors of an object).

[F3]

If a simple module L(μ) occurs in a composition series of M(w∘λ), then μ=u∘λ with u≥w in Bruhat order, so ℓ(u)≥ℓ(w); every composition factor of Ci(λ) therefore has the form L(u∘λ) with ℓ(u)≥i (Jordan-Holder factors of Verma modules dominate the head (BGG 8.12)).

[F4]

For a short exact sequence 0→A→B→C→0 of objects of O the multisets satisfy JH⁡B=JH⁡A⊎JH⁡C; hence equalities of two of the multisets force the equality of the third, and JH⁡A⊆JH⁡B for a subobject A⊆B. Objects of O have finite length and O is abelian (Category O is abelian and extension closed among weight modules, Every object of O has finite length, Composition series and composition factors of an object).

[F5]

The complex B∙(λ) is exact at every degree (it is a resolution), while C∙(λ) is a complex; by hypothesis it is exact at degrees 0,…,k−1 (Weak BGG resolution, The BGG differential from signed Verma maps, Chain complex in an abelian category).

Proof

1.1F2F4F5

The comparison chain. We prove JH⁡ker⁡di=JH⁡ker⁡diB for all 0≤i≤k by induction on i. Base i=0: the augmentation Πλ=B0(λ)/ker⁡d0B=C0(λ)/ker⁡d0 is the same simple module, so JH⁡(B0/ker⁡d0B)=JH⁡(C0/ker⁡d0), and [F2] gives JH⁡B0=JH⁡C0; by the additivity of [F4] applied to 0→ker⁡d0B→B0→B0/ker⁡d0B→0 and to the same sequence for C0, the equality of the middle and quotient multisets gives JH⁡ker⁡d0B=JH⁡ker⁡d0.

2.1F2F4F5step 1.1F1

Induction step. Let 1≤i≤k and assume JH⁡ker⁡di−1B=JH⁡ker⁡di−1. By exactness of B∙ at i−1 we have im⁡diB=ker⁡di−1B, and by the hypothesis of the statement (which covers i−1≤k−1) we have im⁡di=ker⁡di−1; hence JH⁡im⁡diB=JH⁡im⁡di. The first isomorphism theorem applied in the abelian category gives im⁡diB≅Bi/ker⁡diB and im⁡di≅Ci/ker⁡di, so JH⁡(Bi/ker⁡diB)=JH⁡(Ci/ker⁡di). Since JH⁡Bi=JH⁡Ci by [F2], additivity [F4] applied to the two short exact sequences 0→ker⁡diB→Bi→Bi/ker⁡diB→0 and 0→ker⁡di→Ci→Ci/ker⁡di→0 yields JH⁡ker⁡diB=JH⁡ker⁡di.

3.1F4F5step 1.1step 2.1

At i=k, the comparison gives JH⁡ker⁡dk=JH⁡ker⁡dkB. Exactness gives ker⁡dkB=im⁡dk+1B. Applying [F4] to 0→ker⁡dk+1B→Bk+1→im⁡dk+1B→0 yields JH⁡ker⁡dk=JH⁡im⁡dk+1B⊆JH⁡Bk+1.

4.1F2F3step 3.1

By [F2] JH⁡Bk+1=⨆ℓ(w)=k+1JH⁡M(w∘λ), and by [F3] every simple factor in this union is L(u∘λ) with ℓ(u)≥k+1. Hence every composition factor of ker⁡dk is of the form L(u∘λ) with ℓ(u)≥k+1, which proves the main assertion.

5.1F3step 4.1∎

For the equivalent formulation, note first that ker⁡dk⊆Ck(λ), so every factor of ker⁡dk is a factor of Ck(λ) and hence, by [F3], of the form L(u∘λ) with ℓ(u)≥k. Given step 4.1, the condition "no factor of ker⁡dk has the form L(u∘λ) with ℓ(u)≤k" is therefore equivalent to the main assertion.

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