Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-07
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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Every object of O has finite length

Statement

Fix a finite-dimensional complex semisimple Lie algebra g, a Cartan subalgebra h, and a positive Borel b=hn+. Write Q+=iZ0αi, μλ when λμQ+, and wλ=w(λ+ρ)ρ.

Every object of O has a finite composition series and is both Noetherian and Artinian. The length of zero is zero.

Facts & Assumptions

Given: The setting above and the hypotheses in the statement.

[F1]

Fix a finite-dimensional complex semisimple Lie algebra g, a Cartan subalgebra h, and a positive Borel b=hn+. Write Q+=iZ0αi, μλ when λμQ+, and wλ=w(λ+ρ)ρ. Suppose MOχλ. Every nonzero subquotient T of M has Tμ0 for some μWλ. In particular the number of strict inclusions in any finite chain of submodules of M is at most dλ(M)=μWλdimMμ, where distinct weights in the orbit are counted once. (Finite weight-space detection of subquotients)

[F2]

Fix a finite-dimensional complex semisimple Lie algebra g, a Cartan subalgebra h, and a positive Borel b=hn+. Write Q+=iZ0αi, μλ when λμQ+, and wλ=w(λ+ρ)ρ. The category is the categorical direct sum O=χOχ: objects have finite support in the index χ, morphisms between distinct components vanish, and the canonical component projections are exact. (Generalized central-character decomposition of O)

[F3]

Fix a finite-dimensional complex semisimple Lie algebra g, a Cartan subalgebra h, and a positive Borel b=hn+. Write Q+=iZ0αi, μλ when λμQ+, and wλ=w(λ+ρ)ρ. Let M be a finitely generated h-semisimple g-module. Then MO if and only if suppMi=1r(λiQ+) for some finite list of weights. In either case every Mμ is finite dimensional. The list may be empty for M=0; finite generation is an independent hypothesis. (The support description of category O with finite generation)

[F4]

Fix a finite-dimensional complex semisimple Lie algebra g, a Cartan subalgebra h, and a positive Borel b=hn+. Write Q+=iZ0αi, μλ when λμQ+, and wλ=w(λ+ρ)ρ. Every nonzero MO contains a nonzero weight vector killed by n+. (A nonzero O-object has a highest-weight vector)

[F5]

Every central element acts on a cyclic highest-weight module by a scalar. In particular, each cyclic highest-weight module has a well-defined central character in the sense of def-central-character-of-a-lie-algebra-module. (Central elements act by scalars on cyclic highest-weight modules)

Proof

1.1

Split M into its finitely many nonzero generalized central-character summands. Each such summand has a highest-weight vector: the finite-cone support of F3 has a maximal weight above any chosen weight, since simple-root coefficients in the interval are bounded. Central action on this highest line defines a character χλ: a central element preserves the highest line of its cyclic module and commutes with the generator action. The generalized character on this summand must equal that scalar character, since a scalar with a zero power is zero. Thus each summand is indexed by some highest weight λ.

F5F4F2F3algebra
2.1

Apply F1 to each summand and add the bounds. Character projections are exact by F2, so every strict submodule factor has a nonzero projection and contributes at least one to this sum of detectors. All finite strict submodule chains in M consequently have a common finite integer bound. For M=0 the sum and bound are zero.

F1F2step 1.1
3.1

Start with 0M, omitting the inclusion when M=0. If a nonzero factor is not simple, insert the inverse image of a nonzero proper submodule of that factor. Each insertion increases the number of strict inclusions. The bound forces termination and all resulting factors are simple. An infinite ascending or descending chain would have finite initial portions exceeding the same bound. Thus both chain conditions hold.

algebrastep 2.1

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