Alphabeta Math
LemmaStatement: AI-adaptedProof: AI-generatedPipeline-generatedjudge pass (gpt-5.6-terra)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Fine ultrapower seeds and normality

Statement

In ZFC let kappa be regular uncountable, lambda>=kappa a cardinal, and U a fine kappa-complete ultrafilter on P_kappa(lambda). In its collapsed universe ultrapower j:VM, let s=π([xx]U). Then jλsj(λ) and M satisfies s<j(κ). U is normal if and only if s=jλ. In the normal case π([xotp(x)]U)=λ and j(κ)>λ.

Facts & Assumptions

Given: ZFC. Evaluated the identity seed and its internal size by universe Los, proved both normality directions using Scott equality, and identified the normal seed order type externally and internally.

[F1]

Fine measures, strong compactness and supercompactness: Fineness gives each point cone; normality makes a coordinate selection constant on a large set.

[F2]

Countable completeness and transitive collapse: Countable completeness gives a transitive elementary collapse, with the universe Los schema in its dependency.

[F3]

The Axiom of Choice: ZFC propagates from the collapse and cardinal-size conventions.

Proof

1.1

Kappa-completeness and uncountability imply countable completeness, so F2 gives the collapsed ultrapower and its formula-by-formula coordinate equivalence. At every coordinate x, x is a subset of lambda of size below kappa. The equivalence therefore says sj(Pκ(λ)): M regards s as a subset of j(lambda) of size below j(kappa). As M is transitive, the subset statement also holds externally. For each alpha<lambda, the coordinate set where alpha belongs to x is U-large by F1, so j(alpha) belongs to s. All cardinal and collapse uses retain F3.

F1F2F3
2.1

Suppose U normal. Any member of s is the collapsed class of a function f which selects f(x) in x on a U-large set S. On S these are ordinals below lambda, so F1 makes some fibre alpha U-large. Scott equality and injectivity of the collapse identify that member with j(alpha). Together with step 1.1 this proves s=j``lambda. Conversely suppose equality. Given f:S to lambda selecting an element of x on a U-large S, extend f by zero outside S. Its collapsed class belongs to s, hence is j(alpha) for some alpha<lambda. Scott equality says the extended f equals alpha on a U-large set. Intersect with S to obtain the required fibre of the original f. Thus U is normal.

F1F2step 1.1
3.1

At each coordinate, x is a set of ordinals, and its order type is below kappa: it has cardinality |x|<kappa and kappa is an initial ordinal. The formula defining the unique ordinal order type transfers by F2. Thus the collapsed class of x maps to otp(x) is the order type of s computed in M, and is below j(kappa). In the normal case the increasing map j restricted to lambda is an external order isomorphism of lambda with s by step 2.1. The order isomorphism supplied inside M is also an external one, since M is transitive and its graph and domain are sets; uniqueness of ordinal order types therefore makes its value exactly lambda. Hence lambda<j(kappa). This does not replace M's internal size bound by an unsupported external cardinal comparison in the merely fine case.

F2step 1.1step 2.1

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Dependency tree · two levels

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Sources