Alphabeta Math
TheoremStatement: AI-adaptedProof: AI-generatedPipeline-generatedjudge pass (gpt-5.6-terra)
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

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Strong compactness, fine measures and infinitary logic

Statement

In ZFC, for a regular uncountable cardinal kappa, the following are equivalent: kappa is strongly compact; every P_kappa(lambda), for a cardinal lambda>=kappa, carries a fine kappa-complete ultrafilter; every less-than-kappa satisfiable set-sized Lκ,κ theory has a model; and the same compactness assertion holds for Lκ,ω. Languages may have arbitrary set size.

Facts & Assumptions

Given: ZFC. Proved cone-filter completeness, transported fine measures to small subtheories, selected local models via least ranks, applied infinitary Los, and supplied the complete propositional filter-extension converse.

[F1]

Fine measures, strong compactness and supercompactness: Strong compactness is filter extension; fine measures have their point-cone condition.

[F2]

Infinitary Los theorem: Kappa-complete ultraproducts satisfy the infinitary truth equivalence.

[F3]

The Axiom of Choice: AC selects bounded-rank local models and is used with regularity for small unions.

Proof

1.1

Assume filter extension and fix lambda>=kappa. For a in P_kappa(lambda), let C_a be the cone of x containing a. The sets containing some C_a form a proper filter: every cone contains a itself, and C_a intersect C_b=C_(a union b). An intersection of eta<kappa such filter members contains the cone above the union of their witnessing a_xi. F3 selects those witnesses; regularity makes their union have size below kappa (bound all sizes below one cardinal below kappa and use the infinite-cardinal product bound). Thus the filter is kappa-complete. Extend it by F1. Since C_{alpha} belongs to it for each alpha<lambda, the extension is fine.

F1F3
2.1

Assume the fine-measure assertion and fix a theory T as in the L_(kappa,kappa) assertion. Choose a cardinal lambda>=kappa and an injection e:T to lambda. Push a fine measure on P_kappa(lambda) forward by xe1[x] to get a proper kappa-complete ultrafilter W on P_kappa(T). Inverse images preserve all intersections and complements, proving these laws. For every t in T, the inverse image of the cone of small subtheories containing t contains the e(t)-cone, so W is fine.

F1F3step 1.1
3.1

Each small subtheory a has a set model in the common signature. For each a take the least rank rho_a of such a model code. This is uniquely defined by set satisfaction, and Replacement collects the ranks. Separation in V_(rho_a+1) gives the nonempty set of rank-rho_a model codes satisfying a; F3 chooses one for each a. This bounds the choices before AC and does not choose from classes of models. Take their set ultraproduct by W. For each t in T the coordinate truth set contains the cone of a containing t, hence is in W. F2 makes t true in the ultraproduct. Thus T has a model. The L_(kappa,omega) assertion follows by restriction of syntax.

F2F3step 2.1
4.1

Assume the L_(kappa,omega) assertion and let F be a proper kappa-complete filter on a set I. Introduce one constant d and one unary relation R_X for every subset X of I; abbreviate R_X(d) by r_X. Include r_I, not r_empty, the equivalences rIX¬rX, and rξ<ηXξξ<ηrXξ for every eta<kappa and every such sequence of subsets. Also include r_X for each X in F. This is a set theory in L_(kappa,omega), using no quantifier blocks. For any subtheory of size below kappa, the fewer-than-kappa F-members explicitly required have a nonempty intersection by completeness and properness. Take i in it and interpret the predicates on a one-element carrier by r_X true exactly when i belongs to X. Every identity axiom is then true, even those mentioning other subsets, and all the chosen F-requirements hold. Empty collections use I, which is nonempty since F is proper.

F1F3step 3.1
5.1

Compactness yields a full model. Define U to be the subsets X for which r_X is true there. The top and bottom axioms give properness. The intersection identities give kappa-completeness; their binary instances also give upward closure, since X subset Y implies X intersect Y=X and r_X forces r_Y. Complement identities decide exactly one of X and its complement. Thus U is a kappa-complete ultrafilter, and the F-requirements give F subset U. This proves filter extension, closing the cycle of equivalences.

F1step 4.1

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