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The Littlewood-Paley reproducing formula in tempered distributions
Statement
Assume Countable Choice (The Axiom of Countable Choice ()). With the fixed partition and companion operators of The inhomogeneous dyadic frequency partition and its Littlewood-Paley operators:
- for every the partial sums converge to in as , that is in ;
- for every and every , with the Hermitian pairing one has . If in addition and for some , with conjugate to , then the series converges absolutely to and satisfies .
Facts & Assumptions
Given: the fixed partition , companions and operators of The inhomogeneous dyadic frequency partition and its Littlewood-Paley operators; the partial symbols for .
Each lies in , , and , for constants depending only on ; the supports satisfy for and (Existence of a smooth inhomogeneous dyadic frequency partition, The inhomogeneous dyadic frequency partition and its Littlewood-Paley operators).
pointwise with a locally finite sum, and the operators satisfy on for smooth polynomially bounded symbols; for the products are the transposed multiplications by smooth polynomially bounded symbols, and (The inhomogeneous dyadic frequency partition and its Littlewood-Paley operators, Smooth polynomially bounded multipliers on schwartz space).
The distributional pairing is bilinear, with and . is an automorphism of and ; for the map is a continuous linear functional on (Fourier transform of a tempered distribution, Fourier transform is a topological automorphism of tempered distributions, Fourier transform is a topological automorphism of Schwartz space, Schwartz topology and convergence, Weak and strong topologies on tempered distributions).
Parseval's pairing: for , ; consequently, for a real symbol and , writing , (Parseval pairing on Schwartz space, The inhomogeneous dyadic frequency partition and its Littlewood-Paley operators).
For and , : multiply by and use the seminorm bounds. Thus the tail tends to , uniformly when ranges over a bounded subset of ; a sequence converges in exactly when all seminorms tend to (Schwartz topology and convergence).
Holder's inequality and the monotone convergence theorem for nonnegative measurable functions; finite sums act termwise on integrals (Complex Holder, Minkowski, and the quotient norm, Monotone convergence for the integral).
Proof
The partial symbols. For every the function lies in by [F1] and satisfies with by [F2]. For it equals on : a term with vanishes wherever does, and on , so every tail term vanishes on this ball. (For , and no plateau assertion is made.) Moreover, for every multi-index there is , depending only on , with for all and : by the Leibniz rule and [F1] each summand satisfies , and for , while for the bound is just .
The finite duality identity and absolute convergence. For and , [F4] applied to the real symbol gives for each , and summing yields the first identity of part 2. For the series bound, the pointwise Cauchy-Schwarz inequality in gives for every , and integrating the finite sum, which is legitimate termwise by [F6], gives by Holder; hence the nonnegative series converges (its partial sums are increasing and bounded) and dominates , so that series converges absolutely with the stated bound.
The tail vanishes in . For every the products tend to in the Schwartz topology: for multi-indices , the Leibniz rule writes , and every term with is bounded by uniformly in , while, for , the term with satisfies by [F5], since vanishes for . Hence for every pair , which is convergence to in by [F5], uniformly on bounded subsets because the finitely many seminorms in these estimates are uniformly bounded.
Convergence in (part 1). The multiplier composition in [F2] gives for every . For a Schwartz test , the bilinear transposition convention [F3] gives . By step 2.1 the test on the right tends to zero in , and continuity of makes the pairing tend to zero. The same estimates are uniform for in any bounded subset: maps bounded sets to bounded sets, step 2.1 is uniform there, and a continuous functional is bounded by finitely many Schwartz seminorms. Hence the partial sums converge to in both the weak and strong dual topologies.
Identification of the sum (part 2). Apply step 3.1 to the Schwartz test ; the resulting distributional pairing is the Hermitian integral pairing of part 2. Thus in that convention. Step 1.2 identifies each partial sum with and proves absolute convergence with the stated bound, so the sum is .
Depends on
- The inhomogeneous dyadic frequency partition and its Littlewood-Paley operators
- Existence of a smooth inhomogeneous dyadic frequency partition
- Fourier transform of a tempered distribution
- Smooth polynomially bounded multipliers on schwartz space
- Differentiation and polynomial multiplication preserve tempered distributions
- Fourier inversion on Schwartz space
- Parseval pairing on Schwartz space
- Schwartz topology and convergence
- Complex Holder, Minkowski, and the quotient norm
- Monotone convergence for the integral
- The Axiom of Countable Choice ($\mathrm{AC}_\omega$)
- Fourier transform is a topological automorphism of tempered distributions
- Weak and strong topologies on tempered distributions
- Fourier transform is a topological automorphism of Schwartz space
Used by
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Sources
- Loukas Grafakos, Classical Fourier Analysis, 3rd ed. (Springer GTM 249) (standard reference, not scraped)
- Terence Tao, Math 247A Lecture Notes 4 (UCLA, Fall 2006) (standard reference, not scraped)
- Mark Williams, Notes on Harmonic Analysis (January 11, 2022) (standard reference, not scraped)