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LemmaStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-06
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Local Koszul H One Detects First Regularity Failure

Statement

Let (R,m) be Noetherian local, M finite nonzero, and x⊆m. If the first failure of regularity occurs at xj, then H1(K(x;M))≠0.

Proof

technique · direct
1.1givenalgebra

Let x′=(x1,…,xj−1) and N=M/(x′)M. The preceding prefix is regular, so K(x′;M) has zero positive homology and H0=N. The failure at xj gives 0≠Ann⁡N(xj). The cone exact sequence therefore identifies H1(K(x′,xj;M)) with this nonzero annihilator.

2.1step 1.1algebra∎

Append the remaining entries one at a time. If L is the current nonzero first homology and the next entry is y∈m, the cone exact sequence injects L/yL into the new first homology. The module L is finite because it is homology of a bounded complex of finite modules over a Noetherian ring, and Nakayama gives L/yL≠0. Thus first homology remains nonzero through every later entry, proving H1(K(x;M))≠0.

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Dependency tree · two levels

27 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

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