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LemmaStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passjudge pass (gpt-5.6-terra)audited 2026-08-26
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

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The module-fraction relation is an equivalence relation

Statement

For a commutative ring R, a multiplicative subset SR, and a left R-module M, the relation on M×S from Localisation of a module at a multiplicative subset is an equivalence relation.

Facts & Assumptions

Given: A commutative ring R, a multiplicative subset SR, and a left R-module M.

[L1]

In the localisation of a module, (m,s)(n,t) means that u(tmsn)=0 for some uS, and 1S while products of elements of S stay in S (Localisation of a module at a multiplicative subset).

Proof

technique · direct
1.1

Reflexivity holds because 1(smsm)=0, so (m,s)(m,s) for every (m,s)M×S.

L1algebra
1.2

Symmetry holds because u(tmsn)=0 implies u(sntm)=0, so (m,s)(n,t) implies (n,t)(m,s).

L1algebra
1.3

If (m,s)(n,t) via u and (n,t)(p,v) via w, then uwv(tmsn)=0 and uws(vntp)=0; adding these equalities gives uwt(vmsp)=0, so (m,s)(p,v).

L1algebra
2.1

Steps 1.1, 1.2, and 1.3 prove that is an equivalence relation.

step 1.1step 1.2step 1.3

Depends on

Used by

Cited to discharge well-definedness by Localisation of a module at a multiplicative subset.

Dependency tree · two levels

3 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources