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LemmaStatement: Literature-sourcedProof: AI-adaptedprecheck passjudge pass (deepseek-v4-pro + claude-opus-5[1m])audited 2026-08-24
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A matrix has rank at least r exactly when it has a nonzero r-rowed minor

Statement

Let A∈Mm×n(R) and let 1≤r≤min⁡{m,n}. Then rank⁡A≥r if and only if some r-rowed minor of A is nonzero (Submatrices and minors of a rectangular matrix). Equivalently, the rank of A is the largest positive size of a nonzero minor when A≠0, and it is 0 when every entry is zero (The rank of a matrix equals the rank of the linear map x↦Ax).

Facts & Assumptions

Given: A real m×n matrix A and a natural r with 1≤r≤min⁡{m,n}.

Proof

technique · direct
1.1given

Suppose first that the (I,J)-minor is nonzero, and write B=A[I,J] for the corresponding r×r submatrix.

1.2givenL1choose

Conversely, suppose rank⁡A≥r. Choose r independent columns and form the resulting m×r matrix C. Its column rank and hence its row rank are r, so its rows span Rr and contain r independent rows.

2.1step 1.1L1L2

By [L2], B is invertible. If a linear combination of the r columns of A indexed by J vanishes, restricting that equality to the rows in I gives Bc=0, hence c=0. Those columns are independent, so rank⁡A≥r.

3.1step 1.2L2∎

The r×r submatrix determined by those columns and rows has rank r, so [L2] makes its determinant nonzero. This is an r-rowed minor of A, proving the converse and the equivalence.

Depends on

Used by

Dependency tree · two levels

39 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources