Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedprecheck passaudited 2026-08-11
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Row rank equals column rank, and both equal the number of pivots

Statement

For every finite matrix over a field, rrank⁡(A)=crank⁡(A). Both dimensions equal the number of pivots in any echelon form of A.

Facts & Assumptions

Given: A matrix A and an echelon form R of A.

[L1]

The nonzero rows of R form a basis of the row space of A (The nonzero rows of a row echelon form form a basis of the original row space).

[L2]

Let Q be the reduced row echelon form of A. The columns of A whose indices are pivot columns of Q form a basis of the column space of A (The columns of the original matrix indexed by pivot columns form a basis of its column space).

[L3]

Row rank and column rank are the respective dimensions (Row space, column space, nullspace, row rank, column rank and matrix rank).

Proof

technique · direct
1.1

There is one nonzero echelon row for each pivot, so [L1] and [L3] make the row rank equal to the pivot count of R. This applies to every echelon form of A.

L1L3
2.1

Let Q be the RREF of A. Step 1.1 makes the number of pivots of Q equal to the row rank, while [L2] and [L3] make that same number equal to the column rank. Hence the two ranks are equal, and step 1.1 shows that both equal the pivot count of the originally chosen echelon form R. This includes pivot count zero.

step 1.1L2L3∎

Depends on

Used by

Dependency tree · two levels

13 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources