Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-11
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  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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Row rank equals column rank, and both equal the number of pivots

Statement

For every finite matrix over a field, rrank(A)=crank(A).\operatorname{rrank}(A)=\operatorname{crank}(A). Both dimensions equal the number of pivots in any echelon form of AA.

Facts & Assumptions

Given: A matrix AA and an echelon form RR of AA.

[L1]

The nonzero rows of RR form a basis of the row space of AA (The nonzero rows of a row echelon form form a basis of the original row space).

[L2]

Let QQ be the reduced row echelon form of AA. The columns of AA whose indices are pivot columns of QQ form a basis of the column space of AA (The columns of the original matrix indexed by pivot columns form a basis of its column space).

[L3]

Row rank and column rank are the respective dimensions (Row space, column space, nullspace, row rank, column rank and matrix rank).

Proof

technique · direct
1.1

There is one nonzero echelon row for each pivot, so [L1] and [L3] make the row rank equal to the pivot count of RR. This applies to every echelon form of AA.

L1L3
2.1

Let QQ be the RREF of AA. Step 1.1 makes the number of pivots of QQ equal to the row rank, while [L2] and [L3] make that same number equal to the column rank. Hence the two ranks are equal, and step 1.1 shows that both equal the pivot count of the originally chosen echelon form RR. This includes pivot count zero.

step 1.1L2L3

Depends on

Used by

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 39 results over 15 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources