Alphabeta Math
LemmaStatement: AI-adaptedProof: AI-generatedprecheck passaudited 2026-08-01
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

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A maximal acyclic spanning subgraph of a connected graph is a spanning tree

Statement

Let G be a finite connected graph. If F is an acyclic spanning subgraph of G maximal under edge inclusion among such subgraphs, then F is a spanning tree of G.

Facts & Assumptions

Given: A connected graph G and an edge-maximal acyclic spanning subgraph F.

[F2]

A spanning tree is a connected acyclic spanning subgraph (Spanning trees of a graph, Trees, forests, leaves and isolated vertices).

Proof

technique · contradiction
1.1

Suppose F is disconnected, and choose vertices u,v in distinct components of F.

assume-contraF1
1.2

A u-v path in G has a first edge xy whose endpoints lie in distinct components of F.

F3F1
2.1

Adding xy to F cannot create a cycle, because a cycle through xy would contain an x-y path already in F, contrary to the choice of distinct components.

step 1.2
3.1

Thus F+xy is a strictly larger acyclic spanning subgraph, contradicting maximality.

step 2.1
4.1

Hence F is connected, and therefore it is a spanning tree.

F2discharge-contradiction∎

Depends on

Used by

Dependency tree · two levels

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Sources