Alphabeta Math
TheoremStatement: AI-adaptedProof: AI-generatedprecheck passaudited 2026-08-01
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

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A finite graph is connected if and only if it has a spanning tree

Statement

A finite graph G is connected if and only if it has a spanning tree.

Facts & Assumptions

Given: A finite graph G.

[L1]

Every maximal acyclic spanning subgraph of a connected graph is a spanning tree (A maximal acyclic spanning subgraph of a connected graph is a spanning tree).

[F1]

A spanning tree is a connected spanning subgraph (Spanning trees of a graph).

[F2]

A finite graph has only finitely many edge subsets, so the family of acyclic spanning subgraphs has a maximal member.

[F3]

A graph is connected when every two vertices are joined by a path (Connected graphs and connected components defined by the existence of vertex paths).

Proof

technique · direct
1.1

If G is connected, choose a maximal acyclic spanning subgraph F; the edgeless spanning subgraph shows that the choice family is nonempty.

F2
2.1

By L1, F is a spanning tree of G.

step 1.1L1
3.1

Conversely, if G has a spanning tree T, every two vertices are joined by a path in T, hence by a path in G. Thus G is connected.

F1F3∎

Depends on

Used by

Dependency tree · two levels

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Sources