Alphabeta Math
TheoremStatement: AI-adaptedProof: AI-generatedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-01
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  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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A finite graph is connected if and only if it has a spanning tree

Statement

A finite graph GG is connected if and only if it has a spanning tree.

Facts & Assumptions

Given: A finite graph GG.

[L1]

Every maximal acyclic spanning subgraph of a connected graph is a spanning tree (A maximal acyclic spanning subgraph of a connected graph is a spanning tree).

[F1]

A spanning tree is a connected spanning subgraph (Spanning trees of a graph).

[F2]

A finite graph has only finitely many edge subsets, so the family of acyclic spanning subgraphs has a maximal member.

[F3]

A graph is connected when every two vertices are joined by a path (Connected graphs and connected components defined by the existence of vertex paths).

Proof

technique · direct
1.1

If GG is connected, choose a maximal acyclic spanning subgraph FF; the edgeless spanning subgraph shows that the choice family is nonempty.

F2
2.1

By L1, FF is a spanning tree of GG.

step 1.1L1
3.1

Conversely, if GG has a spanning tree TT, every two vertices are joined by a path in TT, hence by a path in GG. Thus GG is connected.

F1F3

Depends on

Used by

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 32 results over 16 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources