Alphabeta Math
LemmaStatement: AI-adaptedProof: AI-generatedPipeline-generated
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Exact conditional covariance of a moving block bootstrap mean

Statement

Fix a positive integer n, observations x1,…,xn∈H, and an integer block length b with 1≤b≤n. Put N=n−b+1, k=⌊n/b⌋, and r=n−kb. For q∈{b}, and also q=r when r>0, define

Sj(q)=∑ℓ=1qxj+ℓ−1,Sˉq=N−1∑j=1NSj(q),Cq=N−1∑j=1N(Sj(q)−Sˉq)⊗(Sj(q)−Sˉq).

Set C0=0. If Xˉn∗ is the mean produced by Moving block bootstrap, then its conditional covariance operator is

n Cov⁡∗(Xˉn∗)=kCb+Crn,

where the Cr term is zero when r=0. Here Cov⁡∗(Z)=E∗[(Z−E∗Z)⊗(Z−E∗Z)].

Facts & Assumptions

Given: Fixed H-valued observations, block size b, and the independent uniform block-start randomization.

[F1]

Moving block bootstrap: It draws independent uniform block starts, concatenates the corresponding consecutive blocks, and truncates only the last block to produce exactly n observations.

Proof

Given: The observations and the bootstrap law in the Statement.

1.1F1givenalgebra

Write n=kb+r, 0≤r<b. The sum of the first n bootstrap observations is the sum of k complete selected block sums and, if r>0, the first r entries of one additional selected block. Conditional on the data, these k+1{r>0} contributions are independent, and the centered covariance of each complete contribution is Cb, while that of the partial contribution is Cr by uniformity of its start.

2.1step 1.1algebra∎

The covariance of a sum of independent centered Hilbert-valued random elements is the sum of their covariance operators: expanding the tensor product leaves only diagonal terms, since each off-diagonal expected tensor is the tensor of a zero mean with a zero mean. Dividing the sum by n to obtain Xˉn∗, and multiplying its covariance by n, gives (kCb+Cr)/n.

Remarks

When r=0, this reduces to nCov⁡∗(Xˉn∗)=Cb/b. The identity is finite-sample and makes no stationarity or moment assumption on an underlying process.

Depends on

Used by

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Sources