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LemmaStatement: AI-adaptedProof: AI-generatedPipeline-generatedjudge pass (gpt-6-luna)
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Exact conditional covariance of a tapered block bootstrap mean

Statement

Fix a positive integer n, observations Y1,…,Yn∈H, an integer block length b with 1≤b≤n and Wb>0, and the taper and scale wb,ab from Tapered block bootstrap. Set Rt=Yt−Yˉn, N=n−b+1, k=⌊n/b⌋, and r=n−kb. For q=b, and also q=r when r>0, define the tapered partial block sum

Tj(q)=ab∑ℓ=1qwb(ℓ)Rj+ℓ−1,Tˉq=N−1∑j=1NTj(q),Vq=N−1∑j=1N(Tj(q)−Tˉq)⊗(Tj(q)−Tˉq).

Set V0=0. If Xˉn∗ is the tapered bootstrap mean, then

n Cov⁡∗(Xˉn∗)=kVb+Vrn,

with the Vr term zero when r=0.

Facts & Assumptions

Given: Fixed observations, a positive taper norm Wb, and the conditional block-index law in the Definition.

[F1]

Tapered block bootstrap: Each resampled block consists of the centered observations multiplied positionwise by abwb(ℓ); the starts are independent uniform indices, and the final block is truncated if necessary.

Proof

Given: The data and bootstrap randomization in the Statement.

1.1F1givenalgebra

Write n=kb+r, 0≤r<b. The sum of the first n tapered bootstrap observations is the sum of k complete tapered block sums and, if r>0, the first r tapered entries of one additional block. Conditional on the data these contributions are independent; their centered covariance operators are Vb and, when present, Vr, because every block start is uniform on the same N choices.

2.1step 1.1algebra∎

Divide the block-sum total by n. Independence and centering eliminate all off-diagonal tensor terms, so Cov⁡∗(Xˉn∗)=n−2(kVb+Vr). Multiplication by n proves the identity.

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