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Zero-mean L2 decomposition over a finite cover

Statement

Let D=⋃i=1NUi be the finite connected star-shaped cover from Finite star-shaped cover of a bounded Lipschitz domain, with measurable partition Ei and normalized tree-edge bumps ψe. For every q∈L02(D) there are qi∈L02(Ui), depending linearly on q, whose zero extensions satisfy q=∑iqi and ∥qi∥L2(Ui)≤Di∥q∥L2(D),Di=1+∣D∣1/2∑e incident to i∥ψe∥2.

Facts & Assumptions

Given: The finite cover, its spanning tree and unit-integral edge bumps; q∈L2(D) with zero integral.

[F1]

The cover has measurable disjoint Ei⊂Ui partitioning D and a connected intersection graph with a spanning tree; each edge bump is supported in the overlap and has integral one. (Finite star-shaped cover of a bounded Lipschitz domain)

[F2]

∥q∥L1(D)≤∣D∣1/2∥q∥L2(D). (Holder's inequality for integrals, including the endpoint cases)

Proof

1.1givenF1construct

Root the finite spanning tree. Set gi=1Eiq, mi=∫Dgi, and let Mi be the sum of mj over the subtree rooted at i. For a nonroot vertex i with parent-edge bump ψi, set qi=gi+∑j child of iMjψj−Miψi; at the root omit the final term. Every summand is supported in Ui by [F1].

2.1givenalgebrastep 1.1

Since each bump integrates to one, a nonroot patch has integral mi+∑jMj−Mi=0 by the subtree identity Mi=mi+∑jMj. At the root, the integral is mroot+∑jMj=Mroot=∑imi=∫Dq=0.

2.2F1algebrastep 1.1

In the sum of all qi, every tree-edge term −Miψi at a child cancels the +Miψi term at its parent, leaving ∑igi=q almost everywhere because the Ei partition D. All coefficients and operations are linear in q.

3.1F2algebrastep 1.1∎

For every subtree, ∣Mi∣=∣∫∪j in subtree iEjq∣≤∥q∥1≤∣D∣1/2∥q∥2 by [F2], and ∥gi∥2≤∥q∥2. The triangle inequality applied to the definition in step 1.1 gives ∥qi∥2≤∥q∥2+∣D∣1/2∥q∥2∑e incident to i∥ψe∥2=Di∥q∥2.

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Sources