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Normalized discounted occupancy is a probability distribution

Statement

Let a finite discounted CMDP, a stationary policy π, its finite-time state-mass vectors μtπ, its normalized discounted occupancy dπ, and the expected discounted signal Jgπ(μ) be as defined above. Each μtπ is a probability distribution, dπ is a probability distribution, and for every real B≥0 and every transition signal g:X→R satisfying ∣g(s,a,ρ,s′)∣≤B for all (s,a,ρ,s′)∈X, the series defining Jgπ(μ) converges absolutely and satisfies ∣Jgπ(μ)∣≤B/(1−γ).

Facts & Assumptions

Given: A finite CMDP with initial distribution μ, discount 0≤γ<1, a stationary policy π, and the recursive state masses and occupancy defined in the linked items. For the signal bound, fix a real B≥0 and a transition signal g:X→R with ∣g(s,a,ρ,s′)∣≤B for every (s,a,ρ,s′)∈X.

[F1]

Finite discounted constrained Markov decision process: μ0π=μ and μt+1π(s′)=∑s,a,ρμtπ(s)π(a∣s)p(s′,ρ∣s,a).

[F2]

Finite Markov decision process with joint reward-transition law: for each admissible (s,a), the joint next-state/reward masses are nonnegative and ∑s′,ρp(s′,ρ∣s,a)=1.

[F3]

Finite Markov decision process with joint reward-transition law: a stationary Markov policy has π(a∣s)≥0 and ∑a∈A(s)π(a∣s)=1.

[F4]

Normalized discounted state occupancy: dπ(s)=(1−γ)∑t≥0γtμtπ(s).

[F5]

Expected discounted-cost feasibility constraint: Jgπ(μ) is the series of finite sums of the time-t transition masses multiplied by g(s,a,ρ,s′) and γt.

[F7]

Absolute convergence and tail bound for bounded discounted rewards: every real sequence bounded in absolute value by B has an absolutely convergent γ-discounted series whose absolute value is at most B/(1−γ).

[F8]

The principle of mathematical induction: a property holding at 0 and preserved from each natural number to its successor holds for every natural number.

Proof

1.1F1F2F3F8givenalgebra

The initial vector μ0π=μ is nonnegative and sums to one. If μtπ is a probability distribution, then the recurrence and [F2]–[F3] give nonnegative next masses and ∑s′μt+1π(s′)=∑s∑a∈A(s)μtπ(s)π(a∣s)∑s′,ρp(s′,ρ∣s,a)=∑sμtπ(s)=1. By [F8], every μtπ is a probability distribution.

2.1F4F6step 1.1algebra

By step 1.1, 0≤μtπ(s)≤1 for every s,t, so each coordinate series in [F4] converges by comparison with the geometric series [F6]. Since S is finite, its coordinate series can be summed termwise, giving dπ(s)≥0 and ∑sdπ(s)=(1−γ)∑t=0∞γt∑sμtπ(s)=(1−γ)∑t=0∞γt=1 by [F6]. Thus dπ is a probability distribution.

3.1F2F3F5F7step 1.1given∎

For each t, the finite transition weights μtπ(s)π(a∣s)p(s′,ρ∣s,a) are nonnegative and sum to one by step 1.1 and [F2]–[F3]. Hence their weighted sum of g has absolute value at most B. Apply [F7] to this bounded sequence of time-t signal sums; the series in [F5] converges absolutely and its absolute value is at most B/(1−γ).

Depends on

Used by

Cited to discharge well-definedness by Expected discounted-cost feasibility constraint, Finite discounted constrained Markov decision process and Normalized discounted state occupancy.

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