Alphabeta Math
Pipeline-generated
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Constrained MDPs and policy safety

1 · Prerequisites

2 · Logical flowchart

3 · Definitions, theorems and proofs

LemmaStatement: Literature-sourcedProof: AI-adaptedjudge pass (gpt-6-luna)Open item page →

Finite-action average total variation is bounded by average KL

Statement

Assume the Axiom of Choice. Let S be a finite nonempty set, let d be a probability distribution on S, and for each s∈S let A(s) be a finite nonempty set with probability distributions qs and ps. On the power-set sigma-algebra of A(s), define

TV⁡A(s)(qs,ps):=12∑a∈A(s)∣qs(a)−ps(a)∣.

Use the directional Kullback–Leibler divergence with natural logarithms, defined by

DKL(qs∥ps):={∑a:qs(a)>0qs(a)log⁡qs(a)ps(a),qs(a)>0⇒ps(a)>0,+∞,otherwise,

and the convention 0log⁡0=0. Put

K:=∑s:d(s)>0d(s)DKL(qs∥ps)∈[0,+∞].

Then

∑s∈Sd(s)TV⁡A(s)(qs,ps)≤K/2,

where the right side is +∞ when K=+∞.

Facts & Assumptions

Given: The Axiom of Choice, a finite nonempty state set, probability weights d(s), and finite nonempty action sets with probability distributions qs,ps.

[A1]

The Axiom of Choice: every family of nonempty sets has a choice function; AC is invoked only to apply the published Pinsker theorem [F3]. The finite sums and weighting arguments are choice-free.

[F1]

Kullback–Leibler divergence: directional KL is +∞ when the first probability law is not absolutely continuous with respect to the second; under absolute continuity it uses the natural logarithm and the convention 0log⁡0=0.

[F2]

Total variation distance for probability laws: event-supremum total variation is sup⁡B∣q(B)−p(B)∣ and has no factor 1/2; on a finite power-set space it must be identified with the displayed half-ℓ1 convention.

[F3]

Pinsker’s inequality with event-supremum total variation: under AC, event-supremum total variation between probability laws is at most DKL(q∥p)/2; the result is immediate if the KL divergence is infinite.

Proof

1.1F2algebraconstruct

Fix one state s. Write Δa=qs(a)−ps(a); since both distributions have mass one, ∑aΔa=0. The set B={a:Δa≥0} consists of the nonnegative differences. The positive and negative parts of Δ therefore have equal sum, each equal to 12∑a∣Δa∣. For every subset C⊆A(s), ∣∑a∈CΔa∣ is at most this common sum, and C=B attains it. Thus the event-supremum total variation in [F2] equals TV⁡A(s)(qs,ps).

2.1A1F1F3step 1.1given

Apply [F3] to the probability measures qs and ps on the finite power-set space, and use step 1.1. This gives TV⁡A(s)(qs,ps)≤DKL(qs∥ps)/2, including the infinite-divergence case.

3.1step 2.1givenalgebra∎

If K=+∞, the asserted inequality holds because each total-variation term is at most one. Suppose K<∞ and put m=K/2. When m=0, step 2.1 gives DKL(qs∥ps)≥2TV⁡A(s)(qs,ps)2≥0 for every state. Since their d-weighted sum is zero, every state with d(s)>0 has zero divergence, so step 2.1 also gives zero total variation there. When m>0, for every x≥0 the square (x−m)2≥0 gives x≤(m+x/m)/2. Apply this with x=DKL(qs∥ps)/2 for states with d(s)>0, multiply by d(s), and sum. Since ∑sd(s)=1 and ∑sd(s)xs=m, the result is ∑sd(s)xs≤m. Step 2.1 now yields the claimed bound.

Remarks

The finite-action equality in step 1.1 uses the event-supremum convention, not the total-variation norm of a signed measure. AC enters only in the KL/Pinsker branch; the finite-sum and weighted square-root arguments are choice-free.

DefinitionDefinition: Literature-sourcedProof: Not applicableOpen item page →

Finite discounted constrained Markov decision process

Definition

Let M=(S,R,(A(s))s∈S,p) be a finite Markov decision process with nonempty state set S and finite nonempty action set A(s) at each state. Put X={(s,a,ρ,s′):s∈S, a∈A(s), ρ∈R, s′∈S}. Let μ be a probability distribution on S, let γ∈[0,1), let m≥1 be an integer, and for each i∈{1,…,m} let bi∈R, Ci≥0, and ci:X→[−Ci,Ci]. A finite discounted constrained Markov decision process (CMDP) is the tuple consisting of M, μ, γ, and the bounded transition-cost functions and thresholds (ci,bi)i=1m. Its immediate reward signal is r(s,a,ρ,s′)=ρ.

For a stationary Markov policy π, define the state-mass sequence recursively by μ0π=μ and

μt+1π(s′):=∑s∈S∑a∈A(s)∑ρ∈Rμtπ(s)π(a∣s)p(s′,ρ∣s,a).

This recurrence defines nonnegative finite-time masses; the result that each μtπ is a probability distribution is established separately.

DefinitionDefinition: Literature-sourcedProof: Not applicablejudge pass (gpt-6-luna)Open item page →

Normalized discounted state occupancy

Definition

Let a finite discounted CMDP and a stationary policy π be given. The column transition matrix Kπ has entry

Kπ(s′,s):=∑a∈A(s)∑ρ∈Rπ(a∣s)p(s′,ρ∣s,a),

so that its column indexed by s gives the next-state distribution from current state s. With the state-mass column vectors μtπ from the CMDP definition, the normalized discounted state occupancy is

dπ(s):=(1−γ)∑t=0∞γtμtπ(s).

This normalization is part of the definition; the occupancy is a probability distribution by the separate well-definedness result below.

DefinitionDefinition: Literature-sourcedProof: Not applicableOpen item page →

Expected discounted-cost feasibility constraint

Definition

Let a finite discounted CMDP have initial distribution μ, discount γ∈[0,1), m bounded transition signals ci, thresholds bi, and finite-time state masses μtπ under a stationary policy π, as defined in the CMDP model. For any bounded transition signal g on (s,a,ρ,s′), define its expected discounted sum under π by

Jgπ(μ):=∑t=0∞γt∑s∈S∑a∈A(s)∑ρ∈R∑s′∈Sμtπ(s)π(a∣s)p(s′,ρ∣s,a)g(s,a,ρ,s′).

The expected discounted reward is Jπ:=Jrπ(μ) for the immediate reward signal r(s,a,ρ,s′)=ρ, and the ith expected discounted cost is Jciπ(μ). The policy π is feasible for the discounted-cost constraints exactly when Jciπ(μ)≤bi for every i∈{1,…,m}. Feasibility constrains these expectations; it does not assert a per-trajectory bound.

LemmaStatement: AI-adaptedProof: AI-generatedjudge pass (gpt-6-luna)Open item page →

Normalized discounted occupancy is a probability distribution

Statement

Let a finite discounted CMDP, a stationary policy π, its finite-time state-mass vectors μtπ, its normalized discounted occupancy dπ, and the expected discounted signal Jgπ(μ) be as defined above. Each μtπ is a probability distribution, dπ is a probability distribution, and for every real B≥0 and every transition signal g:X→R satisfying ∣g(s,a,ρ,s′)∣≤B for all (s,a,ρ,s′)∈X, the series defining Jgπ(μ) converges absolutely and satisfies ∣Jgπ(μ)∣≤B/(1−γ).

Facts & Assumptions

Given: A finite CMDP with initial distribution μ, discount 0≤γ<1, a stationary policy π, and the recursive state masses and occupancy defined in the linked items. For the signal bound, fix a real B≥0 and a transition signal g:X→R with ∣g(s,a,ρ,s′)∣≤B for every (s,a,ρ,s′)∈X.

[F1]

Finite discounted constrained Markov decision process: μ0π=μ and μt+1π(s′)=∑s,a,ρμtπ(s)π(a∣s)p(s′,ρ∣s,a).

[F2]

Finite Markov decision process with joint reward-transition law: for each admissible (s,a), the joint next-state/reward masses are nonnegative and ∑s′,ρp(s′,ρ∣s,a)=1.

[F3]

Finite Markov decision process with joint reward-transition law: a stationary Markov policy has π(a∣s)≥0 and ∑a∈A(s)π(a∣s)=1.

[F4]

Normalized discounted state occupancy: dπ(s)=(1−γ)∑t≥0γtμtπ(s).

[F5]

Expected discounted-cost feasibility constraint: Jgπ(μ) is the series of finite sums of the time-t transition masses multiplied by g(s,a,ρ,s′) and γt.

[F7]

Absolute convergence and tail bound for bounded discounted rewards: every real sequence bounded in absolute value by B has an absolutely convergent γ-discounted series whose absolute value is at most B/(1−γ).

[F8]

The principle of mathematical induction: a property holding at 0 and preserved from each natural number to its successor holds for every natural number.

Proof

1.1F1F2F3F8givenalgebra

The initial vector μ0π=μ is nonnegative and sums to one. If μtπ is a probability distribution, then the recurrence and [F2]–[F3] give nonnegative next masses and ∑s′μt+1π(s′)=∑s∑a∈A(s)μtπ(s)π(a∣s)∑s′,ρp(s′,ρ∣s,a)=∑sμtπ(s)=1. By [F8], every μtπ is a probability distribution.

2.1F4F6step 1.1algebra

By step 1.1, 0≤μtπ(s)≤1 for every s,t, so each coordinate series in [F4] converges by comparison with the geometric series [F6]. Since S is finite, its coordinate series can be summed termwise, giving dπ(s)≥0 and ∑sdπ(s)=(1−γ)∑t=0∞γt∑sμtπ(s)=(1−γ)∑t=0∞γt=1 by [F6]. Thus dπ is a probability distribution.

3.1F2F3F5F7step 1.1given∎

For each t, the finite transition weights μtπ(s)π(a∣s)p(s′,ρ∣s,a) are nonnegative and sum to one by step 1.1 and [F2]–[F3]. Hence their weighted sum of g has absolute value at most B. Apply [F7] to this bounded sequence of time-t signal sums; the series in [F5] converges absolutely and its absolute value is at most B/(1−γ).

DefinitionDefinition: Literature-sourcedProof: Not applicableOpen item page →

Discounted value, action-value, and advantage functions

Definition

Let a finite discounted CMDP, a stationary policy π, and a bounded transition signal g be given. For s∈S, let δs be the initial distribution assigning probability one to s. The state value is Vgπ(s):=Jgπ(δs). For a∈A(s), define the action value and advantage by

Qgπ(s,a):=∑ρ∈R∑s′∈Sp(s′,ρ∣s,a)(g(s,a,ρ,s′)+γVgπ(s′)),Agπ(s,a):=Qgπ(s,a)−Vgπ(s).

Taking g=r gives reward values and advantages; taking g=ci gives the value and advantage for the ith cost. These quantities are finite because the signal is bounded, 0≤γ<1, and the transition law is normalized.

LemmaStatement: Literature-sourcedProof: AI-adaptedjudge pass (gpt-6-luna)Open item page →

Discounted occupancy change is bounded by average policy TV

Statement

Let a finite discounted CMDP and two stationary policies π,π′ be given, with normalized discounted occupancies dπ,dπ′. Define

TV⁡s(π′,π):=12∑a∈A(s)∣π′(a∣s)−π(a∣s)∣

and ∥x∥1:=∑s∈S∣x(s)∣ for a state vector. Then

∥dπ′−dπ∥1≤2γ1−γ∑s∈Sdπ(s)TV⁡s(π′,π).

Facts & Assumptions

Given: A finite CMDP, 0≤γ<1, stationary policies π,π′, and their state-mass vectors and normalized discounted occupancies.

[F1]

Finite discounted constrained Markov decision process: S and each A(s) are finite, p(s′,ρ∣s,a) is a normalized joint law, P(s′∣s,a):=∑ρp(s′,ρ∣s,a) is a probability distribution, and π(a∣s) is a probability distribution over A(s).

[F2]

Normalized discounted state occupancy: dσ=(1−γ)∑t≥0γtμtσ and the column transition matrix is Kσ(s′,s)=∑a,ρσ(a∣s)p(s′,ρ∣s,a).

[F3]

Normalized discounted occupancy is a probability distribution: every μtσ and dσ is a probability distribution.

Proof

1.1F1F4F5givenalgebra

For σ∈{π,π′}, every entry of Kσ is nonnegative and each column sums to one by [F1]. Thus Kσt is column-stochastic for every t, and its induced matrix 1-norm ∥A∥1:=max⁡s∑s′∣A(s′,s)∣ is one. Every entry of Kσt lies in [0,1], so each of the finitely many coordinate series ∑t=0∞γt(Kσt)(s′,s) converges by comparison with [F4]; their limits give convergence of the matrix partial sums in this finite-dimensional norm. The matrix series Gσ:=∑t=0∞γtKσt therefore exists; its finite partial sums satisfy (I−γKσ)∑t=0NγtKσt=I−γN+1KσN+1, whose remainder norm tends to zero by [F5]. The same identity with multiplication on the other side shows Gσ=(I−γKσ)−1.

1.2F1F3algebra

By [F1], for each coordinate s′ of (Kπ′−Kπ)dπ, the triangle inequality gives ∑s′∣((Kπ′−Kπ)dπ)(s′)∣≤∑s,a,s′dπ(s)∣π′(a∣s)−π(a∣s)∣P(s′∣s,a)=2∑sdπ(s)TV⁡s(π′,π), because ∑s′P(s′∣s,a)=1.

2.1F1F2step 1.1algebra

The recurrence in [F1] and the matrix definition in [F2] give μtσ=Kσtμ, hence dσ=(1−γ)Gσμ. The inverse identity Gπ′−Gπ=Gπ′[(I−γKπ)−(I−γKπ′)]Gπ therefore yields dπ′−dπ=γGπ′(Kπ′−Kπ)dπ.

3.1F4step 2.1step 1.2algebra∎

Since ∥Gπ′∥1≤∑t≥0γt=1/(1−γ) by [F4] and column-stochasticity, combine step 2.1 with step 1.2 to obtain the claimed 1-norm bound.

LemmaStatement: Literature-sourcedProof: AI-adaptedjudge pass (gpt-6-luna)Open item page →

Performance-difference identity for an arbitrary bounded baseline

Statement

Let a finite discounted CMDP, a bounded transition signal g, a bounded function f:S→R, and stationary policies π,π′ be given. All sums below over a,ρ,s′ range over A(s),R,S, respectively. For a policy σ define

δfg(s,a,ρ,s′):=g(s,a,ρ,s′)+γf(s′)−f(s),δˉfg,σ(s):=∑a,ρ,s′σ(a∣s)p(s′,ρ∣s,a)δfg(s,a,ρ,s′).

Put

Lπ,fg(π′):=∑sdπ(s)(δˉfg,π′(s)−δˉfg,π(s)).

Then the exact performance-difference identity is

Jgπ′(μ)−Jgπ(μ)=Lπ,fg(π′)1−γ+11−γ∑s(dπ′(s)−dπ(s))δˉfg,π′(s).

Facts & Assumptions

Given: A finite discounted CMDP, bounded g and f, stationary policies π,π′, and 0≤γ<1.

[F1]

Finite discounted constrained Markov decision process: the finite-time state masses obey the one-step transition recurrence with joint masses p(s′,ρ∣s,a).

[F2]

Expected discounted-cost feasibility constraint: Jgσ(μ) is the discounted series of finite sums of g against the time-t transition masses.

[F3]

Normalized discounted state occupancy: dσ(s)=(1−γ)∑t≥0γtμtσ(s).

[F4]

Normalized discounted occupancy is a probability distribution: every μtσ is a probability distribution, and every bounded transition-signal discounted series is absolutely convergent.

Proof

1.1F1givenalgebra

Fix a policy σ. For each t, let etσ be the finite transition-mass sum of g at time t, and let htσ:=∑sμtσ(s)f(s). By [F1] and the definition of δfg, the finite sum of δfg at time t is etσ+γht+1σ−htσ. Summing after multiplication by γt for t=0,…,N telescopes to ∑t=0Nγtetσ−h0σ+γN+1hN+1σ.

2.1F2F3F4F5step 1.1algebra

The remainder satisfies ∣γN+1hN+1σ∣≤γN+1∥f∥∞→0 by [F4] and [F5]. Also ∣δfg∣≤∥g∥∞+(1+γ)∥f∥∞, so [F4] makes its discounted series convergent. Passing to the limit in step 1.1 and using [F2]–[F3] gives Jgσ(μ)=∑sμ(s)f(s)+(1−γ)−1∑sdσ(s)δˉfg,σ(s).

3.1F2F3step 2.1algebra∎

Apply the identity in step 2.1 to σ=π′ and σ=π and subtract; the initial terms ∑sμ(s)f(s) cancel. Add and subtract ∑sdπ(s)δˉfg,π′(s). The first resulting term is Lπ,fg(π′) by its definition, and the second is ∑s(dπ′(s)−dπ(s))δˉfg,π′(s). Dividing by 1−γ>0 gives the claimed identity.

TheoremStatement: Literature-sourcedProof: AI-adaptedOpen item page →

Policy performance bound by average divergence

Statement

Let a finite discounted CMDP, a bounded transition signal g, a bounded function f:S→R, and stationary policies π,π′ be given. For each state define

δˉfg,σ(s):=∑a∈A(s)∑ρ∈R∑s′∈Sσ(a∣s)p(s′,ρ∣s,a)(g(s,a,ρ,s′)+γf(s′)−f(s)),σ∈{π,π′}.

Set ϵfg(π′):=max⁡s∈S∣δˉfg,π′(s)∣ and

Lπ,fg(π′):=∑s∈Sdπ(s)(δˉfg,π′(s)−δˉfg,π(s)),Dπ,f±,g(π′):=Lπ,fg(π′)1−γ±2γϵfg(π′)(1−γ)2∑s∈Sdπ(s)TV⁡s(π′,π),

where TV⁡s(π′,π):=12∑a∈A(s)∣π′(a∣s)−π(a∣s)∣. Then

Dπ,f−,g(π′)≤Jgπ′(μ)−Jgπ(μ)≤Dπ,f+,g(π′).

These total-variation bounds are choice-free. Under the additional Axiom of Choice, define

D‾KLπ(π′∥π):=∑s:dπ(s)>0dπ(s)DKL(π′(⋅∣s)∥π(⋅∣s)),

using natural logarithms and +∞ when the first action law is not absolutely continuous with respect to the second. The same inequalities hold after replacing ∑sdπ(s)TV⁡s(π′,π) by D‾KLπ(π′∥π)/2; when the average KL is infinite, these KL-form inequalities are interpreted as the trivial extended bounds −∞≤Jgπ′(μ)−Jgπ(μ)≤+∞. Taking g=r gives the reward bound, and taking g=ci gives the corresponding bound for each discounted cost.

Facts & Assumptions

Given: A finite discounted CMDP, bounded transition signal g, bounded function f, stationary policies π,π′, and 0≤γ<1.

[A1]

The Axiom of Choice: AC is used only in the KL branch, through the Pinsker theorem and the directional KL definition; the total-variation proof below is choice-free.

[F1]

Finite discounted constrained Markov decision process: the state and action sets are finite and nonempty, the transition/reward mass is normalized, and g is bounded.

[F2]

Expected discounted-cost feasibility constraint: Jgσ(μ) is the expected discounted transition-signal series.

[F3]

Normalized discounted state occupancy and Normalized discounted occupancy is a probability distribution: dσ is the normalized discounted state occupancy and is a probability distribution.

[F4]

Performance-difference identity for an arbitrary bounded baseline: Jgπ′(μ)−Jgπ(μ)=Lπ,fg(π′)/(1−γ)+(1−γ)−1∑s(dπ′(s)−dπ(s))δˉfg,π′(s).

[F5]

Discounted occupancy change is bounded by average policy TV: ∥dπ′−dπ∥1≤2γ(1−γ)−1∑sdπ(s)TV⁡s(π′,π).

[F6]

Finite-action average total variation is bounded by average KL: under AC, the same weighted average of finite-action total variations is at most the square root of half the weighted directional KL.

Proof

1.1F1F2F3F4givenalgebra

By [F1] and [F3], S is finite, dπ,dπ′ are probability distributions, and each finite sum defining δˉfg,π′(s) is bounded by ∥g∥∞+(1+γ)∥f∥∞; hence ϵfg(π′) is finite. By [F2], the returns are the defined bounded-signal discounted sums. The identity [F4] writes their difference as Lπ,fg(π′)/(1−γ) plus the remainder (1−γ)−1∑s(dπ′(s)−dπ(s))δˉfg,π′(s). The triangle inequality gives ∣∑s(dπ′−dπ)δˉfg,π′∣≤∑s∣dπ′−dπ∣∣δˉfg,π′∣≤ϵfg(π′)∥dπ′−dπ∥1.

2.1F5step 1.1algebra

Substitute [F5] into the remainder bound in step 1.1. The resulting error is at most 2γϵfg(π′)(1−γ)−2∑sdπ(s)TV⁡s(π′,π), which gives the two total-variation inequalities.

3.1A1F6step 2.1algebra∎

Assume AC. If D‾KLπ(π′∥π)=+∞, the stated extended KL inequalities are immediate. Otherwise [F6] bounds the average total variation in step 2.1 by D‾KLπ(π′∥π)/2. Replacing the nonnegative error term by this upper bound gives the two KL-form inequalities. This step alone uses AC; steps 1.1–2.1 do not.

AlgorithmAlgorithm: Literature-sourcedProof: Not applicablejudge pass (gpt-6-luna)Open item page →

Sample-based constrained policy optimization update

Definition

Assume the Axiom of Choice for the theoretical average-KL comparison, and let a finite discounted CMDP have cost signals c1,…,cm with thresholds b1,…,bm. Let θ↦πθ be a stationary policy family on an open set U⊆Rd with fixed common support, where d≥1 and the current parameter θk lies in U. Assume its policy coordinates are twice continuously differentiable on a neighborhood of θk. Choose a trust radius δ>0, a backtracking factor β∈(0,1), and a finite backtracking budget L≥0. At iteration k, the finite data batch consists of N≥1 rows (sj,aj,ωj,A^jr,A^1,jc,…,A^m,jc) from trajectories generated in the CMDP under the current policy πθk, where ωj≥0, ∑jωj=1, and πθk(aj∣sj)>0. The advantage estimates are real numbers held fixed during the update, and the batch also includes real baseline-cost estimates J^i,k. The weights and estimates may come from any fixed rollout or critic estimator; this procedure assumes no accuracy property for them. It specifies the exact finite-data trust-region subproblem and line search; implementations that approximate the subproblem solve are discussed separately.

For every θ∈U, define the finite sample surrogates

L^r(θ):=∑j=1Nωj(πθ(aj∣sj)πθk(aj∣sj)−1)A^jr,L^ic(θ):=∑j=1Nωj(πθ(aj∣sj)πθk(aj∣sj)−1)A^i,jc.

and K^(θ):=∑jωjDKL(πθ(⋅∣sj)∥πθk(⋅∣sj)). Put g=∇L^r(θk), ui=(1−γ)−1∇L^ic(θk), H=∇2K^(θk), and qi=J^i,k−bi. The update procedure is:

  1. If H is not symmetric, or if some nonzero x∈Rd satisfies xTHx≤0, return no-step. Otherwise form the local quadratic program

    max⁡x∈RdgTxsubject toqi+uiTx≤0 (i=1,…,m),12xTHx≤δ.

  2. If this program is feasible, let x∗ be its lexicographically least global maximizer. The feasible set is a closed subset of the compact ellipsoid, so the maximizer set is nonempty and compact. Minimize the first coordinate on that set, restrict to its nonempty compact minimizers, and repeat for each coordinate; the resulting point is the lexicographically least maximizer. If the program is infeasible and m=1, compute v=H−1u1. If u1=0, return no-step, since the linearized cost cannot be reduced. Otherwise u1Tv>0 by positive definiteness, and use the cost-recovery proposal x∗=−2δ/(u1Tv) v. If the program is infeasible and m>1, return no-step.

  3. For j=0,…,L, set θj=θk+βjx∗. Accept the first θj in the policy family's parameter domain for which K^(θj)≤δ and every sample cost estimate J^i,k+(1−γ)−1L^ic(θj) is at most bi. If no candidate passes this sample check, return no-step; otherwise output the accepted parameter as θk+1.

For finite constants Di≥0, optional nonnegative bounded transition signals Δi:X→[0,Di] may be included in the supplied cost-advantage and baseline estimates by estimating the shaped costs ci+Δi. The exact theorem concerns exact policies and expectations; the line search above checks only the supplied sample estimates.

Definition references

RemarkRemark: Literature-sourcedProof: Not applicablejudge pass (gpt-6-luna)Open item page →

Practical CPO updates do not inherit exact safety guarantees automatically

Remarks

An expected discounted-cost constraint controls an expectation. It bounds the probability of a specified pathwise violation only when the cost signal is linked to that event; by itself it does not guarantee pathwise safety or safe exploration. The performance theorem concerns exact policy returns. Its total-variation branch is choice-free, while its average-KL branch assumes the Axiom of Choice. The practical CPO update instead uses sample estimates, a linearized reward/cost objective, a second-order KL approximation, conjugate-gradient solves, and a backtracking line search against sample-estimated constraints. Optional nonnegative cost shaping changes the constrained signal but supplies no error bound for the sample estimates or numerical solves. Consequently, the ideal theorem does not by itself certify the sampled iterates' true costs or imply convergence of the implementation; this remark asserts no such guarantee.

4 · Examples, counterexamples and false statements

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