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LemmaStatement: Literature-sourcedProof: Literature-sourcedaudited 2026-09-04
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A nonzero second derivative splits off a signed square with a smooth parameter

Statement

Let m≥0, let U⊆R×Rm be open around (0,0), and let F:U→R be smooth with

F(0,0)=0,∂F∂u(0,0)=0,∂2F∂u2(0,0)≠0.

Then, after shrinking U, there are a sign ε∈{±1}, a smooth function H of the parameter variable, and a smooth local coordinate change (u,y)↦(u′,y) fixing (0,0) such that

F(u,y)=H(y)+ε(u′)2.

Facts & Assumptions

Given: The open set U, the smooth function F, and the derivative hypotheses in the statement.

[L1]

The Euclidean implicit function theorem solves one scalar equation for one variable as a smooth function of the remaining parameters when the relevant partial derivative is invertible (The Euclidean implicit function theorem with derivative formula).

[L2]

A Euclidean map with invertible derivative at a point is a local diffeomorphism there (The Euclidean inverse function theorem).

Proof

technique · local reduction
1.1givenconstruct

If m=0, define A(u):=∫01(1−t) F′′(tu) dt. Then F(u)=u2A(u), A(0)=12F′′(0)≠0, and after shrinking the domain one has εA(u)>0 for ε=sgn⁡(F′′(0)). Putting u′:=uεA(u) gives F(u)=ε(u′)2.

1.2

Assume m>0. Put G(u,y):=∂F/∂u(u,y). Since ∂G/∂u(0,0)=∂2F/∂u2(0,0)≠0, [L1] gives a smooth function ϕ near 0∈Rm with ϕ(0)=0 and G(ϕ(y),y)=0. [L1, given, assume-case[ positive-parameter], construct]

2.1step 1.2algebra

Set F~(s,y):=F(s+ϕ(y),y)−F(ϕ(y),y). Then F~(0,y)=0 and ∂F~/∂s(0,y)=0 for y near 0.

3.1step 2.1construct

Define A(s,y):=∫01(1−t) ∂2F~/∂s2(ts,y) dt. The integral formula gives F~(s,y)=s2A(s,y), and A(0,0)=12 ∂2F/∂u2(0,0)≠0. After shrinking, the sign ε:=sgn⁡(∂2F/∂u2(0,0)) satisfies εA(s,y)>0 everywhere.

4.1L2step 3.1construct

Put β(s,y):=εA(s,y), define u′:=β(s,y)s, and let H(y):=F(ϕ(y),y). Then F(s+ϕ(y),y)=H(y)+ε(u′)2, and ∂u′/∂s(0,0)=β(0,0)≠0, so [L2] makes (s,y)↦(u′,y) a local diffeomorphism at (0,0).

5.1step 1.1step 1.2step 4.1∎

Composing the translation (u,y)↦(u−ϕ(y),y) from step 1.2 with the coordinate change from step 4.1 yields the required local coordinates (u′,y), and the case m=0 is already covered by step 1.1.

Depends on

Used by

Dependency tree · two levels

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Sources