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Open manifolds admit handle filtrations without top-index handles

Statement

Assume the axiom of countable choice. Let M be a nonempty connected open smooth m-manifold without boundary (no compact component, hence noncompact). Then there is a sequence M0⊆M1⊆M2⊆⋯ of compact m-submanifolds with boundary with Mj⊆int⁡Mj+1 and M=⋃jMj such that for every j the band Mj+1∖int⁡Mj has the following presentation: each connected component C of the band has nonempty outgoing boundary ∂+C=C∩∂Mj+1 and admits a handle decomposition relative to ∂−C=C∩∂Mj with no handles of index m. Equivalently, Mj+1 is obtained from Mj by first extending the boundary through a collar, then adding finitely many disjoint components by 0-handles and attaching finitely many further handles of index at most m−1; no m-handle is ever needed. Countable choice also selects one finite handle presentation for each band component; the bands are fixed before these independent selections.

Facts & Assumptions

Given: ACω and a connected open smooth m-manifold M without boundary and with no compact component.

[F1]

The cap-free exhaustion: there are compact m-submanifolds with boundary M0⊆M1⊆⋯ with Mj⊆int⁡Mj+1 and M=⋃jMj, such that no Mj has a cap and every connected component of every band Mj+1∖int⁡Mj has nonempty outgoing boundary (Open manifolds admit exhaustions with no caps).

[L1]

DT-6 dual elimination: a compact connected triad (W;M0,M1) with M1≠∅ admits a handle decomposition relative to M0 with no handles of index dim⁡W, and the conventions of the relative handle decomposition and of a smooth cobordism triad allow the empty incoming face and the empty outgoing face (Dual elimination of top-index handles, Handle decomposition relative to the incoming boundary, Smooth cobordism triad for Morse theory); the proposition assumes ACω.

Proof

technique · direct
1.1F1L2givenconstruct

Fix j and a connected component C of the band Mj+1∖int⁡Mj. The band is a compact m-manifold with boundary and C is a compact connected component of it; the boundary of C is the disjoint union of the faces C∩∂Mj and C∩∂Mj+1, each a closed embedded submanifold of the corresponding boundary, and [L2] supplies collars of both. Hence (C;C∩∂Mj,C∩∂Mj+1) is a compact connected smooth cobordism triad, and its outgoing face C∩∂Mj+1 is nonempty by the cap-freeness in [F1].

2.1L1step 1.1

Apply [L1] to this triad: because the outgoing face is nonempty, C admits a handle decomposition relative to the incoming face C∩∂Mj with no handles of index m=dim⁡C. When the incoming face is empty, the same proposition is applied with the empty incoming face convention, so the presentation begins with 0-handles and again uses no m-handle.

3.1F1L1L2step 2.1construct

The band has finitely many connected components by compactness and local connectedness [L2]. Assembling the presentations of its components and the collar ∂Mj×[0,ε] implicit in the relative convention gives a presentation of Mj+1 from Mj: extend the boundary through the collar, then add each component by 0-handles and further handles of index at most m−1. In particular no m-handle is ever needed.

4.1F1L1L2step 3.1∎

The only in-run suppliers used are [F1] and [L1], both of which assume ACω, and the standard collar and boundary items of [L2]; no handle cancellation, Whitney trick or later page is invoked. The bands have already been fixed; each has finitely many components. Index a band component C by its band number and the least member of a fixed countable coordinate basis contained in int⁡MC. Each component has a nonempty ambient interior, so such a member exists. Distinct components of one band have disjoint interiors and therefore cannot receive the same nonempty basis member. This gives an injection into N×N. Countable choice selects a complete finite handle presentation for each of this at-most-countable family of nonempty witness sets. This proves the claimed filtration and the stated description of the band presentations.

Depends on

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Sources