Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-07
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Points of a fibre product via residue-field tensors

Statement

For scheme morphisms f:XS and g:YS, points of P=X×SY are in bijection with quadruples (x,y,s,r) where f(x)=g(y)=s and rSpec(κ(x)κ(s)κ(y)). The residue field at the corresponding point of P is canonically κ(r).

Facts & Assumptions

Given: The objects, hypotheses and conventions in the statement above.

[F1]

For every field K and scheme X, morphisms SpecKX correspond bijectively to pairs (x,ι) with xX and a field embedding ι:κ(x)K. The identity embedding gives a canonical morphism Specκ(x)X, compatible with all scheme morphisms. More generally, for a nonzero local ring (R,m), morphisms SpecRX correspond to pairs (x,φ) with a local homomorphism φ:OX,xR. Assuming Choice, two field-valued points have the same image in X if and only if they are dominated by a common field-valued point, by compatible embeddings of their fields into a third field. (Field-valued points and local-ring points)

[F2]

For AB,AC, put D=BAC. Given rSpecD, its projections are q={b:b1r} and q={c:1cr}. Their contractions to A coincide at p. The stalk maps are BqDr,b/s(b1)/(s1),CqDr,c/t(1c)/(1t). They are local and induce embeddings κ(q),κ(q)κ(r) agreeing on κ(p). (Projections on primes, stalks and residue fields)

[F3]

Let AC be a unital ring map. For any set of variables (ti) and any ideal IA[ti], (A[ti]/I)ACC[ti]/IC[ti]. Here the extended ideal is generated by the coefficient images of all elements of I. For a multiplicative subset MA, (M1A)ACM1C. These are ring isomorphisms; no flatness, finite-generation or nonzero-ring hypothesis is required. (Presentations and localization under base extension)

[F4]

Every diagram XSY of schemes has a fibre product. Given an affine cover S=iSpecAi and affine covers f1(SpecAi)=jSpecBij and g1(SpecAi)=kSpecCik, the product has open affine cover Spec(BijAiCik). (Existence of all scheme fibre products)

Proof

1.1

F4 gives the product and its compatible affine chart cover. On one chart write AB,C, D=BAC. A prime t of D contracts by F2 to qB, qC and a common pA. Localize D at images of Bq and Cq, then quotient by the images of q and q.

givenF2F4
2.1

F3 identifies the resulting ring with E=κ(q)κ(p)κ(q). Indeed quotienting the two factors gives their residue fields, while their common A-action factors through Ap/pAp; balancing over A is then the same as balancing over that field. The prime t survives this localization and quotient and gives a prime r of E.

F3step 1.1
3.1

Conversely a prime of E contracts to a prime of D containing the two prescribed prime ideals and disjoint from their complements. Its contractions are therefore exactly q,q. Extension and contraction are inverse: localization primes are recovered by clearing denominators, and quotient primes by inverse image. Taking residue fields at either corresponding prime yields the same fraction field of the quotient domain, since only elements nonzero there were inverted. Empty spectra cause no exception to this correspondence.

step 1.1step 2.1algebra
4.1

Intrinsically F1 gives the map Specκ(z)P of any point z, and its projections induce the two field embeddings in F2. Their product map κ(x)κ(s)κ(y)κ(z) has kernel equal to the prime just constructed. Thus the affine correspondences agree on overlaps, proving the global bijection and residue-field assertion, for nonclosed as well as closed points.

F1F2step 3.1

Depends on

Used by

Dependency tree · two levels

16 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources