Alphabeta Math
ExampleConstruction: Literature-sourcedVerification: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-07
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

The affine plane and the pair of generic points

Example

For any field k, Ak1×kAk1≅Ak2 functorially. Nevertheless the product has distinct points over the pair of generic points: in k[x,y], both (0) and (y−x) contract to (0) in each of k[x] and k[y].

Facts & Assumptions

Given: The objects, hypotheses and conventions in the statement above.

[F1]

Let A→B and A→C be maps of commutative unital rings, allowing the zero ring. In the category of all schemes, Spec⁡B×Spec⁡ASpec⁡C≅Spec⁡(B⊗AC). The projections correspond to b↦b⊗1 and c↦1⊗c. (Affine fibre products are spectra of tensor products)

[F2]

For scheme morphisms f:X→S and g:Y→S, points of P=X×SY are in bijection with quadruples (x,y,s,r) where f(x)=g(y)=s and r∈Spec⁡(κ(x)⊗κ(s)κ(y)). The residue field at the corresponding point of P is canonically κ(r). (Points of a fibre product via residue-field tensors)

Verification

1.1givenF1algebra

F1 identifies the product ring with k[x]⊗kk[y]≅k[x,y]: the maps send x⊗1 to x and 1⊗y to y, with inverse on every polynomial specified by these images. Consequently morphisms from every k-scheme T into the plane are compatible pairs of morphisms into the two lines. Empty test schemes are allowed.

2.1F2step 1.1algebra∎

The ring k[x,y] is a domain, so (0) is prime. The quotient by (y−x) is k[x], also a domain, so this is another prime, distinct because y−x≠0. Substitution y=x is injective on either single-variable subring, giving the asserted contractions. F2 explains these as distinct residue-tensor primes over the same point pair. This works over every field, including characteristic two.

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

9 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources