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Descent of modules on a finite principal cover
Statement
Let be a commutative ring and let generate the unit ideal, so that is a finite principal cover. For each let be an -module, and for each pair let be an isomorphism of -modules, subject to and to the cocycle condition on the common localisation for all .
Set and , and let be the -linear maps whose -components are Let be their equalizer. Then for every the projection induces an isomorphism of -modules and these isomorphisms are compatible with the given : for all the natural map followed by equals the natural map . The construction and the proof use no choice principle.
Facts & Assumptions
Given: A commutative ring ; elements generating the unit ideal; -modules ; isomorphisms with and after localisation to .
Localisation of modules is exact: every short exact sequence of -modules localises to a short exact sequence of -modules (Localisation of modules is exact).
Localisation commutes with quotients and with arbitrary direct sums: and . Since a finite product of modules is a finite direct sum, this covers the finite products occurring below (Localisation commutes with quotient modules and arbitrary direct sums).
Proof
Both and are -modules, the maps and are -linear, and sits in the exact sequence ; every is an -module through and every is an -module through , so all localisations below are localisations of -modules.
For an -module on which acts invertibly the localisation map is an isomorphism, with inverse : if in with , then multiplying by gives , so the inverse is well defined, and it is -linear and inverts on the image of ; in particular is the identity.
Localising the exact sequence of step 1.1 at , [F1] makes exact, and [F2] identifies the finite products componentwise, and ; under these identifications the -component of is and the -component of is , so is the set of families with for all .
The projection is -linear and hence induces an -linear map , the identification being the case of step 1.2; on the description of step 2.1, sends a compatible family to its -th component , viewed in .
The map is surjective: given set for every , where and is regarded in through the inverse of the isomorphism of step 1.2; for all the cocycle condition identifies the localisations of and of to , so , and is a compatible family with -th component .
The map is injective: if is a compatible family with , then for every the -component of the compatibility reads , whose left side is by step 1.2, so , and since localising at is an isomorphism on by step 1.2, ; hence .
Consequently every is an isomorphism; for the compatibility with the overlap data, let be a compatible family, whose image under the map induced by followed by is in and whose image under the map induced by is , and the -component of the compatibility in step 2.1 states exactly that these agree; every construction used only the given modules, the given isomorphisms and universal constructions of kernels and localisations, so no choice principle is invoked.
Depends on
Used by
Dependency tree · two levels
11 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- The Stacks Project, Schemes, §§26.5, 26.7, 26.24 (standard reference, not scraped)
- Ravi Vakil, The Rising Sea, 29 August 2022, Chapters 6, 14, 17 (standard reference, not scraped)