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Solutions of projected contact dynamics are unique under the inherited choice assumptions
Statement
Assume Countable Choice and Dependent Choice. Let and , let be nonempty, closed, and convex, and let satisfy for all , with . Any two absolutely continuous solutions of the projected dynamics of Projected contact dynamics and explicit projection Euler step with the same initial state agree on . For , extend the solution convention directly: , , and a solution is the sole map .
Facts & Assumptions
Given: Countable Choice, Dependent Choice, the set and forcing, and two absolutely continuous solution maps in the Statement.
The Axiom of Countable Choice () is inherited through [F4]'s absolutely-continuous FTC.
The axiom of dependent choice: a relation in which every element is related to something admits an -indexed chain is inherited through [F4]'s absolutely-continuous FTC.
For , Projected contact dynamics and explicit projection Euler step: a solution satisfies for almost every .
Gronwall's integral inequality with variable and constant coefficients: if continuous satisfies , then .
The product of two absolutely continuous functions is absolutely continuous and Fundamental theorem of calculus for absolutely continuous functions: products of absolutely continuous real functions are absolutely continuous with the ordinary product derivative almost everywhere, and the integral of that derivative is the endpoint difference.
The Euclidean inner product on : is the singleton zero vector space, with zero inner product and norm.
Proof
If , then and both solution maps are identically zero. Coordinatewise absolute continuity and differentiation are vacuous, and the inclusion is , so this agrees with the extended convention and uniqueness holds.
Assume and let be the two solutions and define and at almost every time where both inclusions hold. By [F1] these belong to and ; [F2] gives .
The function is absolutely continuous by [F4]. At almost every , [F1] and step 1.2 give using the Lipschitz hypothesis and [F5]. Since , [F4] integrates this differential inequality to . Applying [F3] gives for every , so . This argument uses no choices beyond the two axioms already required by [F4].
Depends on
- The Euclidean inner product $\langle x,y\rangle = \sum_{k<n} x_k y_k$ on $\mathbb{R}^n$
- Projected contact dynamics and explicit projection Euler step
- The convex normal-cone operator is maximal monotone and its resolvent is projection
- Gronwall's integral inequality with variable and constant coefficients
- The product of two absolutely continuous functions is absolutely continuous
- Fundamental theorem of calculus for absolutely continuous functions
- Cauchy-Schwarz $\lvert\langle x,y\rangle\rvert \le \lVert x\rVert_2\lVert y\rVert_2$ with its equality case, the triangle inequality for $\lVert\cdot\rVert_2$, the parallelogram law and polarisation
- The Axiom of Countable Choice ($\mathrm{AC}_\omega$)
- The axiom of dependent choice: a relation in which every element is related to something admits an $\mathbb{N}$-indexed chain
Used by
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Sources
- David E. Stewart, Dynamics with Inequalities: Impacts and Hard Constraints (standard reference, not scraped)
- Dimitri P. Bertsekas, 6.253 Convex Analysis and Optimization, Complete Lecture Notes (standard reference, not scraped)