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PUE singular-space invariant decomposition
Statement
Let be the PUE map of Projected-unitary encoding and singular vectors, with positive singular pairs . For every , set
The vectors form an orthonormal family in and the vectors form an orthonormal family in . In the input basis and output basis ,
For , and the complementary vector is absent. A right zero-singular vector satisfies ; a left zero-singular vector satisfies . Let be the orthogonal sum of all positive-singular input planes or lines, , and ; let be the corresponding sum of positive-singular output planes or lines, , and . Then . The residual ambient subspaces and lie in and , and . Thus each named block is invariant under its corresponding projector, with no implicit pairing of the two kernels.
Facts & Assumptions
Given: A PUE and the SVD data from Projected-unitary encoding and singular vectors.
Projected-unitary encoding and singular vectors: , , the positive singular pairs satisfy and , the trailing bases span and , and is unitary.
Every linear map between finite-dimensional real or complex inner product spaces admits a singular value decomposition: every finite-dimensional linear map has complete orthonormal singular bases and a positive-term SVD formula.
Adjoints satisfy , , , and : adjoints reverse products, , and .
The orthogonal projection is the -component in : a vector is the sum of its projection into a subspace and an orthogonal component.
Pythagoras and finite orthogonal sums: orthogonal components have squared norms that add.
Proof
For , [F1] gives . Since preserves inner products by [F1], orthogonal projection and [F6] give . Dividing by the positive square roots shows that the are orthonormal and lie in . The same calculation, using , proves that the are orthonormal in .
If , then has norm one, as does . By the orthogonal decomposition in [F5] and Pythagoras [F6], its component in is zero, so and .
Decompose . Also , where the middle equality uses and the last uses [F1]. Substitution of the first equation yields , which is the displayed matrix.
If , then , so . If , then , so . Every right singular vector lies in and is orthogonal to each and each from the left kernel, since those vectors lie in . For a positive singular vector and a left-kernel vector, , because and . Thus the listed source blocks are mutually orthogonal. Their orthogonal complement is contained in , because the right singular vectors, including a basis of , span . Applying preserves orthogonality. The listed output blocks are also mutually orthogonal: the left singular vectors, including a basis of , span ; the vectors are orthonormal by step 1.1; and for , , since and . The remaining named output vectors lie in , so they are orthogonal to . The output complement is therefore contained in . Since maps each listed source block onto its corresponding output block, it maps the source complement onto the output complement. These are ambient-space decompositions; the residual blocks are not part of or . Each projector phase is scalar on the residual source and output blocks, so no residual component mixes into a projected singular-space block.
Depends on
- Projected-unitary encoding and singular vectors
- The adjoint $T^*:W\to V$ is characterised by $\langle Tv,w\rangle_W=\langle v,T^*w\rangle_V$
- Adjoints satisfy $(S+T)^*=S^*+T^*$, $(\lambda T)^*=\overline\lambda T^*$, $(ST)^*=T^*S^*$, and $T^{**}=T$
- Every linear map between finite-dimensional real or complex inner product spaces admits a singular value decomposition
- The orthogonal projection $P_Wv$ is the $W$-component in $V=W\oplus W^\perp$
- Pythagoras and finite orthogonal sums
Used by
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Sources
- András Gilyén, Yuan Su, Guang Hao Low, and Nathan Wiebe, Quantum singular value transformation and beyond, Definitions 11–14 and Lemma 14 (standard reference, not scraped)
- Andrew M. Childs, Lecture Notes on Quantum Algorithms, Chapter 29 §29.3 (standard reference, not scraped)