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Rademacher randomisation turns dyadic square functions into random signed multipliers

Statement

Assume Countable Choice (The Axiom of Countable Choice (ACω)). For every 0<p<∞ there are constants 0<cp≤Cp<∞ depending only on p with the following property. For every finite set F⊂{0,1,2,… }, every f∈S(Rn) and every x∈Rn, cp(∑j∈F∣Δjf(x)∣2)1/2≤(∫01∣∑j∈Fεj(t)Δjf(x)∣pdt)1/p≤Cp(∑j∈F∣Δjf(x)∣2)1/2. Moreover, for every fixed t∈[0,1) the finite sum ∑j∈Fεj(t)Δjf equals the Fourier multiplier Tmt,Ff with symbol mt,F:=∑j∈Fεj(t)φj∈Cc∞(Rn); integrating the pointwise inequality in x and using Tonelli gives, for every f∈S, cpp∥SFf∥pp≤∫01∥Tmt,Ff∥ppdt≤Cpp∥SFf∥pp. The same statements hold with Δj replaced by the companion operators Δ~j.

Facts & Assumptions

Given: 0<p<∞, a finite set F⊂{0,1,2,… }, a Schwartz function f∈S(Rn) and a point x∈Rn; the fixed partition (φj), operators Δj and kernels Kj of The inhomogeneous dyadic frequency partition and its Littlewood-Paley operators; the square function SFf=(∑j∈F∣Δjf∣2)1/2 of The Littlewood-Paley square function.

[F1]

Khintchine's inequality: for every finite sequence (aj)j∈J of complex numbers and every 0<p<∞ there are 0<cp≤Cp<∞, depending only on p, with cp(∑j∣aj∣2)1/2≤(∫01∣∑jεj(t)aj∣pdt)1/p≤Cp(∑j∣aj∣2)1/2, and the constants are independent of J (Khintchine's inequality for finite Rademacher sums, Rademacher functions on the unit interval).

[F2]

For f∈S the operators act as Δjf=Tφjf=F−1(φjf^), and T is linear in the symbol: for smooth compactly supported symbols m,n one has Tm+Tn=Tm+n on S. The finite sum mt,F:=∑j∈Fεj(t)φj lies in Cc∞(Rn); if F≠∅, writing jF:=max⁡F, its support is contained in {∣ξ∣≤2jF+2}, while for F=∅ it is the zero symbol with empty support (The inhomogeneous dyadic frequency partition and its Littlewood-Paley operators). For f∈S, Tmt,Ff is a Schwartz function and the multiplier action is convolution by the corresponding kernel.

[F3]

(t,x)↦∑j∈Fεj(t)Δjf(x) is measurable on [0,1)×Rn: it is a finite sum of products of Borel functions of t with continuous functions of x (Arithmetic and lattice operations preserve measurability whenever they are defined); hence ∣⋅∣p of it is nonnegative and product-measurable, and Tonelli's theorem applies, in particular ∫01∫Rn∣⋅∣pdx dt=∫Rn∫01∣⋅∣pdt dx (Tonelli's theorem for nonnegative measurable functions on a sigma-finite product).

Proof

technique · direct
1.1F1algebra

Pointwise Khintchine. At the fixed point x apply [F1] to the finite coefficient vector aj:=Δjf(x), j∈F (legitimate because the coefficients are complex numbers); this gives exactly the displayed pointwise two-sided inequality, with constants depending only on p and not on F, f or x.

1.2F2algebra

The random sum is a multiplier. Fix t∈[0,1). By [F2] each Δjf=Tφjf is in S and the multiplier map is linear in its symbol, so ∑j∈Fεj(t)Δjf=Tmt,Ff with mt,F=∑j∈Fεj(t)φj∈Cc∞(Rn); in particular Tmt,Ff∈S and ∫Rn∣Tmt,Ff∣pdx<∞.

2.1F3step 1.1step 1.2algebra

The integrated inequality. By [F3] the function ∣∑j∈Fεj(t)Δjf(x)∣p is nonnegative and product-measurable, and SFf is measurable by The Littlewood-Paley square function; the pointwise inequality of step 1.1 passes to the x-integral, so cpp∥SFf∥pp≤∫Rn∫01∣∑jεj(t)Δjf(x)∣pdt dx≤Cpp∥SFf∥pp. Since the inner expression equals ∣Tmt,Ff(x)∣p by step 1.2, Tonelli [F3] rewrites the middle term as ∫01∥Tmt,Ff∥ppdt; the quantities are finite because a finite sign vector takes only finitely many values, each corresponding random sum is Schwartz, and a finite sum of Schwartz moduli lies in Lp for every p>0 by choosing decay exponent M with Mp>n.

3.1F1F2step 1.1step 2.1algebra∎

Companions. Replacing Kj by K~j, φj by φ~j and Δj by Δ~j throughout, steps 1.1 to 2.1 apply verbatim with SF replaced by S~Ff=(∑j∈F∣Δ~jf∣2)1/2, because the companion symbols are again compactly supported smooth functions and the Khintchine inequality is insensitive to the coefficients.

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