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Real Clifford block-rotation index bounds

Statement

Assume AC. Let γ be a nonminimizing endpoint-fixed geodesic from Jl to −Jl in a Clifford centriole Pl, with the normalized trace metric. Let sj be the real dimension of an irreducible negative-square Clifford module. If l≢2(mod4), then ind⁡γ≥p/sl+1−1. If l=4m−2, let w be determinant winding under J↦JJl−1 into U(p/2). For d>0, the inequality p−4∣w∣≥4dsl implies ind⁡γ>d. The first estimate is non-strict; its use for connectivity requires additional strict slack.

Facts & Assumptions

[A1]

The Axiom of Choice is assumed; it implies the countable-choice assumptions in the differential-geometric suppliers. No stronger choice principle is introduced. (The Axiom of Choice).

[F1]

The tangent conditions and totally geodesic trace-metric embedding hold; ambient parallel translation is exp⁡(−tad⁡X/2) and its curvature operator is −ad⁡X2/4. (Clifford centrioles and geodesic tangent conditions).

[F2]

The negative-square real Clifford classification determines the irreducible dimensions; there is one irreducible type except at indices congruent to 3 modulo 4. (Real and complex Clifford algebra classification with explicit signature).

[F3]

For E=12∫01∣γ˙∣2, the fixed-endpoint energy Hessian equals the index form I; for the unhalved energy it is 2I, with the same index and kernel. Killing variations are Jacobi fields. (Second variation formula for energy, Killing fields restrict to Jacobi fields along geodesics).

Proof technique: direct construction.

Given: The data and hypotheses in the Statement.

Proof

technique · direct construction
1.1A1F1F2algebra

Write γ(t)=exp⁡(πtA)Jl. By [F1], A commutes with Ji for i<l and anticommutes with Jl. Split Rp orthogonally into minimal subspaces Mh invariant under these operators. The symmetric operator −A2 commutes with the family; hence on a minimal block it is kh2I. The endpoint equation exp⁡(πA)=−I makes kh an odd positive integer. On that block J′=A/kh is a complex structure and JlJ′ extends the Clifford family. The extended module is irreducible, since any proper invariant subspace would be invariant under A and the original family. If all kh=1, the geodesic has length π and is minimal; otherwise some kh≥3.

2.1F1F2step 1.1construct

Suppose l≢2(mod4). The unique irreducible Cl+1 type is equivalent to its last-generator sign reversal. Thus a pair Mj,Mh may be isometrically identified preserving the first l generators and reversing the extra generator. Orthogonalize an intertwiner T by T(T∗T)−1/2, which still intertwines. On the pair the generator becomes diag⁡(kjJ′,−khJ′). Put B=(0−II0) there and zero elsewhere. It commutes with the original family, so conjugation by exp⁡(uB) gives endpoint-fixed geodesics in Pl.

3.1F1F3step 2.1algebra

The Jacobi field of this variation is [B,γ(t)]. Put b=(kj+kh)/2. Substituting the two diagonal exponentials and transporting back by exp⁡(−tad⁡πA/2) gives 2sin⁡(πbt) times a fixed nonzero off-diagonal matrix, up to a constant sign. Thus the field is sin⁡(πbt)Vjh(t) for a nonzero parallel tangent field. Its curvature eigenvalue is (πb)2, consistent with the ambient factor 1/4. It is tangent intrinsically because it arises from the variation in step 2.1, and total geodesy preserves its tangent parallel translation.

4.1F1F3step 1.1step 3.1algebra

For a=1,…,b−1 set Wjh,a(t)=sin⁡(πat)Vjh(t). These fields vanish at both endpoints and satisfy I(Wjh,a,Wjh,a)=((πa)2−(πb)2)∣Vjh∣2/2<0. Sine orthogonality makes different modes orthogonal for I. Different unordered block pairs have disjoint off-diagonal support, preserved by parallel translation and curvature; hence their derivative and curvature pairings are zero in the trace metric. Their full span is therefore negative definite, not merely linearly independent. Fix one nonminimal block h. Each other block gives b≥2 and at least one negative direction. There are r−1 such blocks, with r=p/sl+1, proving the weak bound.

5.1F1F3step 4.1construct

For the initial group stage l=0, split the skew generator into orthogonal real two-planes. On a pair of planes, the two commuting quaternionic S3 factors of SO(4) have speeds (kj+kh)/2 and (kj−kh)/2 in units of π. A nonminimal plane paired with any other plane has a factor of absolute speed at least two. Its two perpendicular sine fields yield at least two negative directions. Their pair supports are orthogonal as in step 4.1, giving index at least p−2, and therefore at least p/s1−1. The factorization can be checked directly by left and right multiplication by unit quaternions on H; the tangent vectors with equal and opposite planar angles give its two orthogonal factors.

5.2F1F2step 3.1step 4.1algebra

Now let l=4m−2 and put i=J1⋯Jl−1. Then i2=−I; it commutes with A and its predecessors and anticommutes with Jl. The complex eigenspaces of A relative to i are invariant under the whole family, because Jl reverses both A and i. Minimality gives A=khi on each block, now with signed odd kh, and the blocks are irreducible Cl modules of size sl. On two identified blocks A=diag⁡(kji,khi). The same rotation computation gives b=∣kj−kh∣/2, and hence b−1 independent negative sine fields when b≥2. Therefore ind⁡γ≥∑kj>kh(kj−kh2−1). All terms are nonnegative integers.

6.1step 1.1step 5.2algebra∎

The map J↦JJl−1 is complex linear relative to i. The determinant of the endpoint −I equals one since p is divisible by four, so its path determinant is a loop. The winding formula is w=(sl/4)∑hkh. Let k+ be the sum of the positive kh and k− minus the sum of the negative ones. Then k++k−≥p/sl and k+−k−=4w/sl. The stated inequality implies k+,k−≥2d. If some kj≥3, its pair contributions against the negative blocks sum to at least (N−+k−)/2>d, where N−≥1 is their number. If some kh≤−3, reverse signs and use the positive blocks. Otherwise all entries are ±1, making the path minimal. This proves the winding estimate with strictness exactly as stated.

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