How statement and proof provenance work
The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.
- Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
- AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
- AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.
These labels describe origin, not correctness: citations and verification chips remain separate evidence.
A regular pencil has no nonzero vector in both kernels
Statement
If is a regular pencil and satisfies and , then .
Facts & Assumptions
Given: A regular pencil of order .
Regular matrix pencils and homogeneous generalized eigenvalues: regularity means is a nonzero polynomial.
For , the determinant over a commutative ring by the Leibniz formula, and for a real matrix: determinant is defined by the finite Leibniz sum.
A nonzero polynomial of degree over an integral domain has at most distinct roots: a nonzero polynomial of degree over an integral domain has at most distinct roots.
A finite-dimensional linear operator over a field is invertible if and only if its determinant is nonzero: a finite-dimensional operator is invertible exactly when its determinant is nonzero.
Proof
Suppose and . Then for every , so is not invertible. By [F4], for every complex .
By [F2], has degree at most . If were nonzero, [F3] would bound its number of distinct complex roots by , while step 1.1 gives every as a root. In particular, the distinct numbers would all be roots, contradicting [F1].
Depends on
- Regular matrix pencils and homogeneous generalized eigenvalues
- For $n\ge1$, the determinant over a commutative ring by the Leibniz formula, and $|\det A|$ for a real matrix
- A nonzero polynomial of degree $n$ over an integral domain has at most $n$ distinct roots
- A finite-dimensional linear operator over a field is invertible if and only if its determinant is nonzero
Used by
Dependency tree · two levels
23 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Daniel Kressner, Numerical Methods and Software for General and Structured Eigenvalue Problems (PhD dissertation, 2004), Chapter 2: The QZ Algorithm (standard reference, not scraped)
- LAPACK Users' Guide, Generalized Nonsymmetric Eigenproblems (standard reference, not scraped)