Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-adaptedPipeline-generated
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A regular pencil has no nonzero vector in both kernels

Statement

If (A,B) is a regular pencil and x∈Cn satisfies Ax=0 and Bx=0, then x=0.

Facts & Assumptions

Given: A regular pencil A−λB of order n≥1.

[F1]

Regular matrix pencils and homogeneous generalized eigenvalues: regularity means det⁡(A−λB) is a nonzero polynomial.

[F3]

A nonzero polynomial of degree n over an integral domain has at most n distinct roots: a nonzero polynomial of degree d over an integral domain has at most d distinct roots.

[F4]

A finite-dimensional linear operator over a field is invertible if and only if its determinant is nonzero: a finite-dimensional operator is invertible exactly when its determinant is nonzero.

Proof

1.1givenF1F4algebraassume-contra

Suppose x≠0 and Ax=Bx=0. Then (A−λB)x=0 for every λ∈C, so A−λB is not invertible. By [F4], f(λ)=det⁡(A−λB)=0 for every complex λ.

2.1givenF1F2F3step 1.1contradictiondischarge-contradiction∎

By [F2], f has degree at most n. If f were nonzero, [F3] would bound its number of distinct complex roots by n, while step 1.1 gives every λ∈C as a root. In particular, the n+1 distinct numbers 0,1,…,n would all be roots, contradicting [F1].

Depends on

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