How statement and proof provenance work
The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.
- Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
- AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
- AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.
These labels describe origin, not correctness: citations and verification chips remain separate evidence.
Associated graded algebra of an ideal generated by a regular sequence
Statement
Let be a commutative ring and let be an -regular sequence (Regular Sequence On A Module), with (The ideal generated by a subset and principal ideals) and associated graded ring (The associated graded ring and associated graded module of an ideal-adic filtration). The canonical graded homomorphism
is an isomorphism. In particular is free over on the classes of , and . No Noetherian or domain hypothesis is required.
Facts & Assumptions
Given: A commutative ring , an -regular sequence (Regular Sequence On A Module) and the ideal (The ideal generated by a subset and principal ideals) with its associated graded ring (The associated graded ring and associated graded module of an ideal-adic filtration).
Regular Sequence On A Module: A finite ordered sequence in is -regular when and multiplication by is injective on for every , and . In particular the truncated sequence is likewise -regular, and is a nonzerodivisor on for .
The associated graded ring and associated graded module of an ideal-adic filtration: For an ideal , the associated graded ring is with multiplication ; in particular it is commutative and generated in degree one.
The ideal generated by a subset and principal ideals: is the ideal generated by the : it consists of the finite sums with , and each .
Proof
The degree- monomials in the generate , so the displayed graded map is surjective. To prove injectivity it suffices to show that every homogeneous relation has all : a relation lying in can be made zero by subtracting a degree- expression whose coefficients lie in . We prove this coefficient assertion by induction on the sequence length . For , and the associated graded ring has only degree zero, where the map is the identity.
Suppose and the assertion holds for . Fix and write the relation as , where and . We induct on . If , the assertion for puts all coefficients in . If , reduction modulo gives . By the coefficient assertion for (also applicable to an expression lying in the next power), for every . Since is a nonzerodivisor on , every lies in .
Consequently ; express it as . Absorb into and remove the term with exponent . This gives a relation of the same degree with largest exponent . Its modified coefficients are and its other coefficients are unchanged. The induction on puts all modified coefficients in , hence all original ones in , since . Together with the coefficients of , this proves the assertion and completes the induction on .
The coefficient assertion proves injectivity in every degree. In degree one, the isomorphism identifies with on the displayed classes. The symmetric algebra of this free module is the polynomial algebra, yielding the canonical symmetric-algebra identification. Only regularity of the ordered sequence and ideal-power generation were used.
Remarks
The double induction is on the length of the sequence (step 3.1) and, inside a fixed length, on the highest power of occurring in the relation (step 4.1). The lemma is the algebraic input to the computation of the normal cone of a regular immersion and to the identification of the associated graded algebras used in the deformation of the resolution theorem.
Depends on
Used by
Dependency tree · two levels
8 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- The Stacks Project, Commutative Algebra, Section 10.69, Quasi-regular sequences (standard reference, not scraped)