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Associated graded algebra of an ideal generated by a regular sequence

Statement

Let R be a commutative ring and let f1,…,fc be an R-regular sequence (Regular Sequence On A Module), with J=(f1,…,fc) (The ideal generated by a subset and principal ideals) and associated graded ring gr⁡JR=⨁n≥0Jn/Jn+1 (The associated graded ring and associated graded module of an ideal-adic filtration). The canonical graded homomorphism

(R/J)[X1,…,Xc]⟶gr⁡JR,Xi⟼fi mod J2,

is an isomorphism. In particular J/J2 is free over R/J on the classes of f1,…,fc, and Sym⁡R/J(J/J2)=gr⁡JR. No Noetherian or domain hypothesis is required.

Facts & Assumptions

Given: A commutative ring R, an R-regular sequence f1,…,fc∈R (Regular Sequence On A Module) and the ideal J=(f1,…,fc) (The ideal generated by a subset and principal ideals) with its associated graded ring gr⁡JR (The associated graded ring and associated graded module of an ideal-adic filtration).

[F1]

Regular Sequence On A Module: A finite ordered sequence f1,…,fc in R is R-regular when R/(f1,…,fi−1)≠0 and multiplication by fi is injective on R/(f1,…,fi−1) for every i, and R/(f1,…,fc)≠0. In particular the truncated sequence f1,…,fc−1 is likewise R-regular, and fc is a nonzerodivisor on R/J′ for J′=(f1,…,fc−1).

[F2]

The associated graded ring and associated graded module of an ideal-adic filtration: For an ideal J⊆R, the associated graded ring is gr⁡JR=⨁n≥0Jn/Jn+1 with multiplication (a+Jm+1)(b+Jn+1)=ab+Jm+n+1; in particular it is commutative and generated in degree one.

[F3]

The ideal generated by a subset and principal ideals: J=(f1,…,fc) is the ideal generated by the fi: it consists of the finite sums ∑icifi with ci∈R, and each fi∈J.

Proof

1.1F2F3

The degree-n monomials in the fi generate Jn, so the displayed graded map is surjective. To prove injectivity it suffices to show that every homogeneous relation ∑∣I∣=naIfI=0 has all aI∈J: a relation lying in Jn+1 can be made zero by subtracting a degree-n expression whose coefficients lie in J. We prove this coefficient assertion by induction on the sequence length c. For c=0, J=0 and the associated graded ring has only degree zero, where the map is the identity.

2.1F1step 1.1

Suppose c>0 and the assertion holds for J′=(f1,…,fc−1). Fix n and write the relation as ∑e=0lHefce=0, where He=∑∣I′∣=n−eaI′,efI′ and l≤n. We induct on l. If l=0, the assertion for J′ puts all coefficients in J′⊂J. If l>0, reduction modulo (J′)n−l+1 gives fclHl∈(J′)n−l+1. By the coefficient assertion for J′ (also applicable to an expression lying in the next power), fclaI′,l∈J′ for every I′. Since fc is a nonzerodivisor on R/J′, every aI′,l lies in J′.

3.1F3step 2.1

Consequently Hl∈(J′)n−l+1; express it as ∑∣I′′∣=n−l+1bI′′fI′′. Absorb fcHl into Hl−1 and remove the term with exponent l. This gives a relation of the same degree with largest exponent l−1. Its modified coefficients are aI′′,l−1+fcbI′′ and its other coefficients are unchanged. The induction on l puts all modified coefficients in J, hence all original ones in J, since fcbI′′∈J. Together with the coefficients of Hl, this proves the assertion and completes the induction on c.

4.1F1step 1.1step 3.1∎

The coefficient assertion proves injectivity in every degree. In degree one, the isomorphism identifies (R/J)c with J/J2 on the displayed classes. The symmetric algebra of this free module is the polynomial algebra, yielding the canonical symmetric-algebra identification. Only regularity of the ordered sequence and ideal-power generation were used.

Remarks

The double induction is on the length c of the sequence (step 3.1) and, inside a fixed length, on the highest power l of fc occurring in the relation (step 4.1). The lemma is the algebraic input to the computation of the normal cone of a regular immersion and to the identification of the associated graded algebras gr⁡JR used in the deformation δk(C′)=δk(C)−r(m2) of the resolution theorem.

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