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LemmaStatement: AI-adaptedProof: AI-generatedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-02
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Assuming dependent choice, the Samuel uniformity induces the original topology

Statement

Assume dependent choice. The topology induced by US\mathcal U_S equals the topology induced by U\mathcal U.

Facts & Assumptions

Given: Dependent choice, an original-open set OXO\subseteq X, and a point xOx\in O.

[L1]

The Samuel uniformity is coarser than the original uniformity (Samuel function pseudometrics generate a uniformity coarser than the original one).

[L2]

Entourage balls form a neighbourhood base for the induced topology (The sets containing an entourage ball about each of their points form a topology).

[L4]

A normal sequence gives a uniformly continuous pseudometric pp with {p22}E1\{p\le2^{-2}\}\subseteq E_1 (A normal sequence of entourages yields a uniformly continuous pseudometric with controlled dyadic balls).

[L5]

The ball of a Samuel coordinate is a Samuel entourage-ball (The Samuel uniformity generated by bounded uniformly continuous functions).

Proof

technique · constructive
1.1

Since USU\mathcal U_S\subseteq\mathcal U, every Samuel-open set is original-open.

L1L2
1.2

Choose UUU\in\mathcal U with U[x]OU[x]\subseteq O, take the sequence of [L3], and take the pseudometric pp of [L4]; then {y:p(x,y)1/4}O\{y:p(x,y)\le1/4\}\subseteq O.

L2L3L4
1.3

Put f(y)=min{1,4p(x,y)}f(y)=\min\{1,4p(x,y)\}. The reverse triangle inequality for a pseudometric and the uniform continuity of pp make ff uniformly continuous, so fFUf\in\mathcal F_{\mathcal U} and f(x)=0f(x)=0.

L4construct
2.1

The Samuel neighbourhood {y:f(y)f(x)<1}\{y:|f(y)-f(x)|<1\} lies in {y:p(x,y)<1/4}O\{y:p(x,y)<1/4\}\subseteq O, so every original-open set is Samuel-open.

L5step 1.2step 1.3
3.1

The two inclusions in steps 1.1 and 2.1 give equality of the topologies; for X=X=\varnothing both are the empty topology.

step 1.1step 2.1discharge-construct

Depends on

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