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The isotropic contact elasticity form is well defined and bounded

Statement

In the setting of Small-strain elasticity with a frictionless contact gap, the form a is well defined, symmetric, and satisfies ∣a(u,v)∣≤(2μ+2λ)∥u∥H1(Ω)∥v∥H1(Ω)(u,v∈V).

Facts & Assumptions

Given: The bounded polygon Ω, u,v∈V⊂H1(Ω;R2), constants μ>0, λ≥0, and the form in Small-strain elasticity with a frictionless contact gap.

[F1]

The strain and form are ε(u)=(∇u+(∇u)T)/2 and a(u,v)=∫Ω2με(u):ε(v)+λdiv⁡udiv⁡v dx. (Small-strain elasticity with a frictionless contact gap)

[F2]

For L2 matrix or scalar fields, the integral pairing is bounded by the product of the L2 norms. (Cauchy-Schwarz inequality for L2)

[F3]

The H1 norm contains the L2 norm of the full weak gradient, and the entries of that gradient are in L2. (Integer-order Sobolev spaces and their norms)

Proof

technique · direct

Given: The setting above and the real isotropic elasticity form a.

1.1F1F3givenalgebra

The symmetric-part map is an orthogonal projection in the Frobenius inner product, so ∣ε(w)∣F≤∣∇w∣F. Also ∣div⁡w∣=∣tr⁡∇w∣≤2∣∇w∣F by Cauchy–Schwarz on the two diagonal entries. Thus both ε(w) and div⁡w are in L2 by [F3], so each integral defining a(u,v) is finite.

2.1F1F2F3step 1.1algebra∎

Applying [F2] to the two terms of [F1] and then the bounds of step 1.1 gives ∣a(u,v)∣≤2μ∥∇u∥2∥∇v∥2+2λ∥∇u∥2∥∇v∥2≤(2μ+2λ)∥u∥H1∥v∥H1. The integrand is symmetric in u,v, so a(u,v)=a(v,u).

Depends on

Used by

Cited to discharge well-definedness by Small-strain elasticity with a frictionless contact gap.

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