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LemmaStatement: Literature-sourcedProof: AI-generatedPipeline-generatedjudge pass (gpt-6-luna)
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A Ck+r residual vanishing through order r−1 has a Ck scaled extension

Statement

Let P⊆Rn be open, let r∈{1,2}, let k∈N with k≥1, and let δ>0. Let f:(−δ,δ)×P→Rm be Ck+r. Suppose ∂hjf(0,α)=0 for every α∈P and 0≤j<r. Then f(h,α)/hr, initially defined for h≠0, has a Ck extension F to (−δ,δ)×P. Its mixed derivatives at zero satisfy ∂hℓ∂αβF(0,α)=ℓ!(r+ℓ)!∂hr+ℓ∂αβf(0,α)(ℓ+∣β∣≤k).

Facts & Assumptions

Given: The hypotheses in the Statement.

[F1]

Multivariable Taylor formula with a Lagrange remainder along a line segment: a Cs+1 map on a convex neighborhood has its degree-s Taylor polynomial with a remainder of order s+1 along each line.

[F2]

The chain rule for total derivatives: D(g∘f)(a)=Dg(f(a))∘Df(a): differentiating a composition with a coordinate line gives the corresponding directional derivative.

Proof

1.1givenF2

For each parameter multi-index β with ∣β∣≤k, iteratively apply the chain rule [F2] to the identities ∂hjf(0,α)=0. Thus ∂αβ∂hjf(0,α)=0 for every 0≤j<r, as needed below.

2.1F1F3step 1.1algebra

For each parameter multi-index β with ∣β∣≤k, put kβ=k−∣β∣, N=r+kβ, and gβ(h)=∂αβf(h,α). For every s≤kβ, put m=N−s. If m≥2, apply [F1] componentwise to gβ(s) through degree m−1; continuity of its highest derivative lets us replace the Lagrange coefficient at θh by its value at zero plus o(1). If m=1, subtract the linear Taylor polynomial: the derivative of the remainder is o(1) by continuity, so [F3] gives a remainder o(∣h∣). Thus in every case gβ(s)(h) equals its Taylor polynomial through degree m plus o(∣h∣m). By step 1.1 all coefficients of degrees below r vanish. For h≠0, the quotient rule expresses the ℓth derivative of gβ/hr as a finite linear combination of h−r−ℓ+sgβ(s)(h), 0≤s≤ℓ. Substituting the expansions shows that the remainder terms are o(∣h∣kβ−ℓ); the polynomial part has a continuous extension whose ℓth derivative at zero is ℓ!∂hr+ℓ∂αβf(0,α)/(r+ℓ)!. Continuity of the derivatives on compact parameter neighborhoods makes these limits locally uniform in α.

3.1step 2.1algebra∎

Define the value at h=0 by the displayed limit formula. For each ∣β∣+ℓ≤k, step 2.1 gives a locally uniform limit for the corresponding derivative as h→0; at h=0 these formulas are differentiable in α because f is Ck+r, and their h-derivatives agree with the next displayed coefficient. Induction on total derivative order therefore shows that all mixed partial derivatives through order k exist and are continuous across h=0. The extension is Ck with the asserted formula.

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Sources