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The standard polynomial resolution has an augmentation contraction and is admissible
Statement
Let be a map of commutative unital rings (Commutative ring) and let be its standard polynomial simplicial resolution (The standard simplicial resolution of a ring map), where forgets the algebra structure. Its augmentation is termwise surjective, a homotopy equivalence of underlying simplicial sets over the constant set , and a trivial Kan fibration. Its associated -module complex is a free resolution of , so is an admissible polynomial resolution for computing cotangent complexes.
Facts & Assumptions
Given: A map of commutative unital rings and its standard resolution with , faces and degeneracies induced by the counit and unit of the free-forgetful adjunction.
, ; the free-forgetful adjunction has unit , comultiplication , and counit ; the augmentation is induced by the structure map of ; each is a polynomial -algebra, hence a free -module on its monomials (The standard simplicial resolution of a ring map, The polynomial ring as finitely supported coefficient families on monomials).
A termwise surjective homomorphism of simplicial abelian groups inducing a quasi-isomorphism of associated complexes is a trivial Kan fibration; a homomorphism of simplicial abelian groups that is a homotopy equivalence of underlying simplicial sets induces a quasi-isomorphism on associated complexes (Normalized simplicial chains, prism homotopies and the abelian trivial-fibration criterion).
Proof
The extra degeneracy. Let be the map induced by the unit of the free-forgetful adjunction, including the augmented map . Directly on the nested polynomial expressions defining , the adjunction triangle identities give , , and , with the augmented interpretations in degrees and . These identities say that is an extra degeneracy for the augmented simplicial set underlying .
Homotopy over . For an order-preserving map with initial zeros, consider the map , where is interpreted using the augmentation when . Write this map as . The identities of step 1.1 give for and for ; similarly for and for . At the all-zero endpoint , the repeated face map lands in and the same identities use the augmentation. Deleting or repeating the -th vertex of changes its number of initial zeros by exactly the stated amount. Since faces and degeneracies generate all order maps, these equations prove simplicial naturality, so the maps assemble into a simplicial homotopy over from the composite of the augmentation with the constant section (the all-zero endpoint) to the identity of (the all-one endpoint). Augmentation followed by that section is therefore homotopic to the identity, while the other composite is the identity on ; hence the augmentation is a homotopy equivalence of underlying simplicial sets over . Every augmentation map is surjective because the nested variables lift every .
Admissibility. By [F2] the underlying-set homotopy equivalence of step 2.1 makes the associated chain map of abelian groups a quasi-isomorphism, and the termwise surjectivity of the augmentation then makes a trivial Kan fibration. Each is a free -module by [F1], so the associated complex, reindexed cohomologically in nonpositive degrees, is a complex of free -modules with and vanishing higher homology; it is therefore a free resolution of , and is admissible for computing cotangent complexes. The extra degeneracy is only a map of sets, not an algebra-linear chain contraction; it is the normalization and prism lemma [F2] that passes the contraction from underlying simplicial sets to module homology.
Depends on
Used by
- Independence of the cotangent complex from the chosen simplicial resolution Lemma
- The fixed-base simplicial cotangent module represents derived derivations Lemma
Cited to discharge well-definedness by The standard simplicial resolution of a ring map.
Dependency tree · two levels
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Sources
- The Stacks Project, Chapter 14 (Simplicial Methods), Example 14.34.5 and Chapter 92 (The Cotangent Complex) (standard reference, not scraped)