Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-6-luna)verified 2026-10-22 (gpt-6.1-sol)
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The standard genus-zero hat diagram of the unknot has rank one

Statement

Let U be the standard oriented unknot and take its genus-zero one-pointed Heegaard diagram: Σ=S2, each handlebody is a three-ball, there are no α- or β-curves, and one w-point and one z-point are joined by trivial arcs in the two balls. The associated-graded hat chain complex has one generator, zero differential, and homology of rank one over F2. This is a computation for the stated diagram; it makes no invariance claim for other diagrams.

Facts & Assumptions

Given: The genus-zero, one-pointed diagram specified in the statement.

[F1]

Admissible multipointed Heegaard data for knot Floer complexes defines Sym⁡m(Σ), the product tori, and their intersection points as generators; its hat specialization sets the basepoint variable to zero.

[F2]

Admissible multipointed Heegaard data for knot Floer complexes defines the differential by counts of classes of Maslov index 1.

Proof

1.1F1givenconstruct

Here h=0 and k=1, so m=h+k−1=0. The empty products of α- and β-curves both map to the unique point of Sym⁡0(S2), which is a singleton. By [F1], this intersection is the entire generator set, so the chain group has dimension one.

2.1F1F2step 1.1algebra∎

Every map into a singleton is constant, so there is only the constant class in π2(x,x). Its pullback tangent bundle is zero-dimensional; hence the linearized Cauchy–Riemann operator has zero kernel and cokernel and Maslov index 0. Thus there is no class of Maslov index 1 to contribute under [F2]. The differential is zero, and the homology equals the one-dimensional chain group.

Depends on

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Sources