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Symmetric difference formula for Fourier partial sums
Statement
Let be a one-period integrable function, let , and let . Then
Equivalently,
Facts & Assumptions
Given: A one-period integrable function , reals , and an integer .
Fourier partial sums are Dirichlet convolutions: (Fourier partial sums are Dirichlet convolutions).
The Dirichlet kernel is even and (Dirichlet and Fejer kernels).
Proof
By [L1], because [L2] gives .
Split the integral in step 1.1 at and substitute on . Since is one-periodic and by [L2], this yields
The first displayed formula is step 2.1 with the two summands reordered. Replacing by the closed form from [L3] gives the second displayed formula.
Depends on
Used by
Dependency tree · two levels
4 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Richard S. Laugesen, Harmonic Analysis Lecture Notes (standard reference, not scraped)
- Loukas Grafakos, Classical Fourier Analysis, 3rd ed. (standard reference, not scraped)