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The cycle-boundary diagram associated to a short exact sequence of complexes
Statement
Let be a short exact sequence of complexes in an abelian category, and fix . Write Then the differentials induce a commutative diagram in which the top row is exact at and , and the bottom row is exact at and .
Facts & Assumptions
Given: The short exact sequence of complexes in the statement and an integer .
A short exact sequence of complexes is exact in each degree in the ambient abelian category (Short exact sequence of complexes).
Cycles are kernels of outgoing differentials and boundaries are images of incoming differentials (Cycle and boundary subobjects of a complex).
For a morphism of short exact sequences, the induced kernel row is exact at its first two nodes and the induced cokernel row is exact at its last two nodes (The kernel row and cokernel row of a morphism of short exact sequences are exact at two nodes each).
Proof
Apply [L3] to the commutative square in degree . Using [L2], its cokernel row is exactly so the top row is exact at and .
Apply [L3] to the commutative square in degree . By [L2], the resulting kernel row is exact at and . The two rows are connected by the differentials, and the chain-map equalities from [L1] make the diagram commutative.
Depends on
Used by
Dependency tree · two levels
12 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Charles A. Weibel, Chapter 1 of An Introduction to Homological Algebra (standard reference, not scraped)
- The Stacks Project, Section 12.13: Complexes (standard reference, not scraped)