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LemmaStatement: AI-adaptedProof: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-10
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The interval homotopy operator is coordinate independent

Statement

The interval operator K:Ωk(M×[0,1])Ωk1(M) is coordinate independent and maps smooth forms to smooth forms.

Facts & Assumptions

Given: A smooth form ω up to the endpoints of M×[0,1].

[F1]

Integration along the unit interval for a differential form: Let ωΩk(M×[0,1]) be smooth up to the endpoints. For k1, its interval integral is the (k1)-form Kω=01βtdt, where ω=αt+dtβt and both families are tangential to M. Set K=0 on degree zero and on zero terms. Use the product structure of prop-products-of-smooth-manifolds-have-a-canonical-product-smooth-structure, restricted from M×R. The families are intrinsically αt=itω and βt=it(ιtω), using def-interior-product-of-a-form-by-a-vector-field; evaluation on tangential tuples and on (t,v1,,vk1) proves existence and uniqueness of the decomposition. The integral is in the fixed finite-dimensional fibre k1TxM. Coefficients have smooth local extensions across endpoints. thm-differentiation-under-the-integral-sign-on-a-compact-rectangle supplies parameter differentiation; coordinate independence and full smoothness are proved in lem-the-interval-homotopy-operator-is-coordinate-independent.

[F2]

Leibniz's rule on a compact rectangle: an interior parameter derivative with a continuous extension may be passed through a Riemann integral: Let a<b and c<d. Suppose g,h:[a,b]×[c,d]R are continuous and, for every fixed t[c,d], the function xg(x,t) is differentiable on (a,b) with derivative h(x,t). Define G(x):=cdg(x,t)dt. Then G is differentiable on [a,b] as a function on that interval and G(x)=cdh(x,t)dt(x[a,b]). At a and b the derivative is relative and one-sided. The derivative hypothesis is imposed only for interior parameter values; continuity of h supplies its endpoint values.

Proof

technique · direct
1.1

The coefficient family βt=it(ιtω) is intrinsically a form in the fixed fibre at x. A change of coordinates on M multiplies its coefficient vector by the exterior-power transition matrix A(x), which does not depend on t. Finite-dimensional integration gives 01A(x)βt(x)dt=A(x)01βt(x)dt. Thus the local integral expressions transform as a form.

F1given
2.1

Fix a smaller closed coordinate rectangle about a point of M. Each coefficient b(x,t) and all its derivatives are continuous on that rectangle times [0,1], by local smoothness up to endpoints. Applying compact-parameter differentiation with the other coordinates fixed gives xj01b(x,t)dt=01xjb(x,t)dt. The right side is jointly continuous, since uniform continuity on the compact rectangle bounds the difference of integrals by the supremum difference of integrands. Repetition for every multi-index proves all coordinate derivatives exist and are continuous. Hence Kω is smooth. For k=0, K=0 is smooth directly.

F1F2step 1.1

Source locator

Lee, Introduction to Smooth Manifolds, 2nd ed., Lemma 17.9 and Proposition 17.10, pp.444–445; the proof here computes the product differential directly.

Depends on

Used by

Cited to discharge well-definedness by Integration along the unit interval for a differential form.

Dependency tree · two levels

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Sources