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The interval homotopy operator is coordinate independent
Statement
The interval operator is coordinate independent and maps smooth forms to smooth forms.
Facts & Assumptions
Given: A smooth form up to the endpoints of .
Integration along the unit interval for a differential form: Let be smooth up to the endpoints. For , its interval integral is the -form , where and both families are tangential to . Set on degree zero and on zero terms. Use the product structure of prop-products-of-smooth-manifolds-have-a-canonical-product-smooth-structure, restricted from . The families are intrinsically and , using def-interior-product-of-a-form-by-a-vector-field; evaluation on tangential tuples and on proves existence and uniqueness of the decomposition. The integral is in the fixed finite-dimensional fibre . Coefficients have smooth local extensions across endpoints. thm-differentiation-under-the-integral-sign-on-a-compact-rectangle supplies parameter differentiation; coordinate independence and full smoothness are proved in lem-the-interval-homotopy-operator-is-coordinate-independent.
Leibniz's rule on a compact rectangle: an interior parameter derivative with a continuous extension may be passed through a Riemann integral: Let and . Suppose are continuous and, for every fixed , the function is differentiable on with derivative . Define Then is differentiable on as a function on that interval and At and the derivative is relative and one-sided. The derivative hypothesis is imposed only for interior parameter values; continuity of supplies its endpoint values.
Proof
The coefficient family is intrinsically a form in the fixed fibre at . A change of coordinates on multiplies its coefficient vector by the exterior-power transition matrix , which does not depend on . Finite-dimensional integration gives . Thus the local integral expressions transform as a form.
Fix a smaller closed coordinate rectangle about a point of . Each coefficient and all its derivatives are continuous on that rectangle times , by local smoothness up to endpoints. Applying compact-parameter differentiation with the other coordinates fixed gives . The right side is jointly continuous, since uniform continuity on the compact rectangle bounds the difference of integrals by the supremum difference of integrands. Repetition for every multi-index proves all coordinate derivatives exist and are continuous. Hence is smooth. For , is smooth directly.
Source locator
Lee, Introduction to Smooth Manifolds, 2nd ed., Lemma 17.9 and Proposition 17.10, pp.444–445; the proof here computes the product differential directly.
Depends on
Used by
Cited to discharge well-definedness by Integration along the unit interval for a differential form.
Dependency tree · two levels
11 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Nigel Hitchin, Differentiable Manifolds (2014) (standard reference, not scraped)
- John M. Lee, Introduction to Smooth Manifolds, second edition (standard reference, not scraped)