Alphabeta Math
LemmaStatement: AI-adaptedProof: AI-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-08-31
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A star-expansion of a forest containing a long path contains the corresponding cycle

Statement

Let r≥1, and let F be a forest containing an induced path on vertices b1,…,br+1 in this order, and let F⋆ be the star-expansion of F. Then F⋆ contains an induced cycle on

r+4

vertices.

Facts & Assumptions

Given: An integer r≥1, a forest F containing the induced path b1−b2−⋯−br+1, and its star-expansion F⋆ with root v and teeth a1,…,ar+1 matched to those path vertices.

[L1]

In the star-expansion, the only new edges are vai and aibi (The star-expansion of a graph).

Proof

technique · direct finite check
1.1given

Consider the vertex set {v,a1,b1,…,br+1,ar+1}. Along this set the displayed edges va1,a1b1,b1b2,…,brbr+1,br+1ar+1,ar+1v form a cycle of length r+4.

2.1step 1.1L1

No other edge joins two vertices of this set. The forest path contributes only the consecutive edges bibi+1, since it is induced in F, and [L1] shows that a1 and ar+1 meet only their matched path vertices and the root. Hence the chosen vertices induce exactly that cycle.

3.1step 2.1∎

Therefore F⋆ contains an induced cycle on r+4 vertices.

Depends on

Used by

Dependency tree · two levels

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Sources