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LemmaStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedverified 2026-10-22 (gpt-6.1-sol)
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Enhanced A-polynomial of a torus knot

Statement

Assume full AC and let a>b≥2 be coprime positive integers. With the meridian-longitude and exponent conventions used for the enhanced A-polynomial, the enhanced A-polynomial of Ta,b is, up to multiplication by a Laurent unit, A~Ta,b(M,L)={1+M2aL,b=2,−1+M2abL2,b>2. If K is the unknot, then A~K=1. The nontrivial torus-knot Newton polygon is therefore a line segment whose slope in the (a,b)↦MbLa convention is ab.

Facts & Assumptions

Given: Full AC, the oriented positive coprime torus knot and original meridian-longitude and Newton-coordinate conventions.

[F1]

The actual torus-knot group/peripheral supplier gives G=⟨x,y∣xa=yb⟩, central h=xa=yb, positive meridian μ=yαxβ with aα+bβ=1, and preferred longitude λ=hμ−ab (Torus-knot exterior group and peripheral system).

[F2]

For exactly these group words, the complete irreducible peripheral eigenvalue-locus ideal is (1+M2aL) for b=2 and (M2abL2−1) for b>2. The proof supplies explicit irreducible matrix families with a cofinite set of meridian values and proves the exact radical ideal, including exceptional representations (Irreducible peripheral eigenvalue curves of a torus presentation).

[F3]

The crossing-free unknot has group Z, by the actual one-generator, no-relator calculation in Explicit unknot and figure-eight oriented Wirtinger codes.

[F4]

The enhanced A-polynomial defines the reduced union of one-dimensional peripheral eigenvalue-image closure components from irreducible characters, with primitive integer normalization (The enhanced A-polynomial).

Proof

1.1F1F2F4givenconstructalgebra

Apply [F1] with the given positive integers a,b. Its meridian and longitude are exactly the words required in [F2], including the sign and order of the positive meridian. For b=2, [F2] gives a single graph L=−M−2a with exact ideal (1+M2aL). For b>2 it gives the two graphs L=±M−ab with exact ideal (M2abL2−1). Each graph is a one-dimensional closed copy of C∗ under its meridian coordinate; the exact graph ideals in [F2] prove that no additional isolated or other-dimensional image component contributes. The reduced union in [F4] therefore has precisely the displayed equation. These integer polynomials are primitive because their nonzero coefficients are 1,−1, and square-free because [F2] identifies the graph ideals as distinct prime ideals with radical intersection. Thus they have the asserted normalization up to a Laurent unit.

1.2F3F4givenalgebra

For the unknot, [F3] identifies a representation with a single determinant-one matrix. Its complex eigenvector supplies a line invariant under that matrix and all its positive and negative powers. Hence there is no irreducible representation of the unknot group. The defining enhanced curve union in [F4] is empty, with unit vanishing ideal, so its primitive generator is 1. This argument concerns only the unknot and makes no converse detection claim requiring instanton theory.

2.1F1step 1.1givenalgebra∎

In the specified exponent coordinates a monomial MjLi corresponds to (i,j). The two terms for b=2 give points (0,0) and (1,2a), so the segment has slope 2a=ab. For b>2 the points are (0,0) and (2,2ab), so the slope is again ab. Multiplication by a Laurent unit translates both points and leaves the slope unchanged. The group/peripheral supplier retains its original full-AC hypothesis, whereas the new finite matrix calculation adds no choice principle. This proves every clause with the original positive-knot and peripheral conventions.

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