Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-6-luna)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A transverse predictor hyperplane selects one nearby point of a regular branch

Statement

Let c:[−δ,δ]→U⊆Rn+1 be a unit-speed reparameterization of the unique locally normalized solution curve supplied by A regular solution curve has a unique local arclength chart and a quadratic predictor defect, with c(0)=z0. Let τ∈Rn+1 be a unit vector, let 0<r−,r+≤δ, and suppose that for some κ>0, τTc′(s)≥κ(−r−≤s≤r+). Let zp∈Rn+1 satisfy d:=τT(zp−z0),0≤d≤κr+. Then there is exactly one s∗∈[−r−,r+] such that τT(c(s∗)−zp)=0. Thus the predictor hyperplane has exactly one intersection with this local branch segment containing its basepoint. The statement is local to the supplied chart.

Facts & Assumptions

Given: The chart c, z0, unit normal τ, r−, r+, κ, and zp with the conditions in the Statement.

[F1]

A regular solution curve has a unique local arclength chart and a quadratic predictor defect: c is a C1 unit-speed reparameterization of the unique local solution curve on an interval containing [−r−,r+].

[F2]

The chain rule for total derivatives: D(g∘f)(a)=Dg(f(a))∘Df(a): the derivative of a linear functional composed with a differentiable curve is the functional applied to the curve derivative.

[F4]

If f≤g on [a,b] and both are integrable then ∫abf≤∫abg; and m(b−a)≤∫abf≤M(b−a): an integrable function bounded below by κ on an interval of length ℓ has integral at least κℓ.

Proof

Given: The chart and inequalities in the Statement.

1.1F1F2F3F4F5givenalgebra

Define g(s):=τT(c(s)−zp) on [−r−,r+]. By [F2], g′(s)=τTc′(s)≥κ. The fundamental theorem in [F3] therefore gives g(r+)−g(0)=∫0r+g′(u) du≥κr+ by [F4]. Since g(0)=−d and d≤κr+, we have g(0)≤0 and g(r+)≥0. If d=0, then s∗=0 is a zero; if d>0, the intermediate value theorem [F5] gives s∗∈(0,r+] with g(s∗)=0.

2.1F2F3F4step 1.1algebra∎

If −r−≤s1<s2≤r+, [F2]–[F4] give g(s2)−g(s1)=∫s1s2g′(u) du≥κ(s2−s1)>0. Thus g is strictly increasing, so it has at most one zero on [−r−,r+]. The zero found in step 1.1 is therefore unique.

Depends on

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Sources