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LemmaStatement: Literature-sourcedProof: AI-generatedprecheck passaudited 2026-08-29
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The trivial words of a recursively presented group form a recursively enumerable language

Statement

Let ⟨X∣R⟩ be a recursive presentation. Then the language of words on X⊔X−1 that represent the identity in the presented group is recursively enumerable.

Facts & Assumptions

Given: A recursive presentation ⟨X∣R⟩ and a word w on X⊔X−1.

[L1]

In a presentation ⟨X∣R⟩, a word represents the identity exactly when it lies in the normal closure of R inside the free group on X. (In ⟨X∣R⟩, the words u and v represent the same element if and only if u−1v∈⟨ ⁣⟨R⟩ ⁣⟩)

[L2]

The normal closure of R is the set of finite products of conjugates of elements of R and their inverses. (The normal closure of R is the set of finite products of conjugates of elements of R and their inverses)

Proof

technique · direct
1.1givenL2

Because the relator language of the recursive presentation is recursively enumerable, there is a procedure that lists all relator words in R and hence also all pairs (r,ε) with r∈R and ε∈{1,−1}. By dovetailing over lengths, one can therefore enumerate all finite lists of conjugators and signed relators.

2.1L1L2step 1.1

First freely reduce the input word w to a reduced word w‾. For each finite list from step 1.1, form the corresponding product of conjugates from [L2] and freely reduce it in the ambient free group. Whenever the result is w‾, accept. If w is trivial in the presented group, then [L1] and [L2] supply a relator expression representing the same free-group element as w, so its free reduction is w‾ and the search eventually halts; if w is nontrivial, the search may run forever.

3.1step 2.1algebra∎

Hence the trivial words are exactly the words on which this procedure halts, so they form a recursively enumerable language.

Depends on

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Sources