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The actual-to-predicted ratio approaches one at small radii away from stationarity
Statement
Let be the model of Quadratic trust-region models and the actual-to-predicted reduction ratio, with , symmetric , and radius . Suppose for a declared , and is on an open set containing the segment from to . Suppose the gradient of is -Lipschitz on that segment, meaning there. Let , let be feasible, and suppose for the Cauchy step of The Cauchy step for a quadratic trust-region model. Interpret if , and assume . Then the predicted reduction is positive and Consequently, for , if and then . If , then .
Facts & Assumptions
Given: The model, the smoothness and Hessian-bound assumptions in the Statement, and a feasible step satisfying the stated fraction of Cauchy decrease.
The Cauchy step for a quadratic trust-region model: if , then ; if , then .
The Cauchy step gives a quantitative model decrease: with the zero-matrix convention from that lemma.
The mean value theorem, as the case of Cauchy's: for continuous on with and differentiable on there is with : if a scalar function is continuous on a closed interval and differentiable in its interior, its endpoint difference equals its derivative at an interior point times the interval length.
.
The gradient Lipschitz inequality in the Statement holds along the segment , .
with .
Proof
Given: The hypotheses in the Statement.
Put and . By [F3] and [F4], . If , [F1] gives . If , then and ; since , [F1] again gives . Put . If , [A1] gives ; if , use the zero-matrix convention in [F2]. Hence [F2] and [A3] imply
Define and . For , the gradient Lipschitz bound and [F4] give By [F5] on over , . From the model formula and [A1], Since , step 1.1 yields If , the numerator vanishes and ; otherwise the stated threshold gives , hence .
Depends on
- Quadratic trust-region models and the actual-to-predicted reduction ratio
- The Cauchy step for a quadratic trust-region model
- The Cauchy step gives a quantitative model decrease
- Induced matrix norms are compatible with matrix-vector multiplication, submultiplicative, and satisfy ||I|| = 1
- Cauchy-Schwarz $\lvert\langle x,y\rangle\rvert \le \lVert x\rVert_2\lVert y\rVert_2$ with its equality case, the triangle inequality for $\lVert\cdot\rVert_2$, the parallelogram law and polarisation
- The mean value theorem, as the case $g(x) = x$ of Cauchy's: for $f$ continuous on $[a,b]$ with $a < b$ and differentiable on $(a,b)$ there is $c \in (a,b)$ with $f(b) - f(a) = f'(c)(b-a)$
Used by
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Sources
- Jorge Nocedal and Stephen J. Wright, Numerical Optimization, second edition (standard reference, not scraped)
- Nick Gould, Continuous Optimization Algorithms, Part 3.2: Trust-Region Methods (standard reference, not scraped)