Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-adaptedprecheck passaudited 2026-08-13
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The exact edge count of Tn,r and the unique balancing maximum among complete r-partite graphs

Statement

Let r≥1 and write n=qr+a with 0≤a<r. Then

e(Tn,r)=(n2)−a(q+12)−(r−a)(q2)=12(n2−a(q+1)2−(r−a)q2).

Among complete r-partite graphs on n vertices, this is the maximum edge count. Equality holds exactly when all part sizes differ by at most 1, hence exactly for a graph isomorphic to Tn,r. Also

e(Tn,r)≤r−12rn2,

with equality exactly when r divides n.

Facts & Assumptions

Given: The hypotheses and notation of the statement above.

[F1]

For n=qr+a, Tn,r is the complete r-partite graph with a parts of size q+1 and r−a parts of size q (Ordinary-subgraph extremal number ex⁡(n,H), Turán graph Tn,r, and balanced blowup H[s]).

[F2]

If V has n elements, the complete graph KV has exactly (n2) edges (The complete graph on an n-element vertex set has (n2) edges).

[F3]

(nk) is the number of k-element subsets of an n-element set (The set [A]k of k-element subsets and the binomial coefficient (nk):=∣[n]k∣).

Proof

technique · count missing within-part pairs and balance parts
1.1

A complete multipartite graph contains every vertex pair except pairs within one part. If its part sizes are n1,…,nr, its edge count is (n2)−∑i(ni2)=12(n2−∑ini2). Substituting the a sizes q+1 and the remaining sizes q gives both displayed exact formulas.

givenF1F2F3
2.1

If ni≥nj+2, moving one vertex from part i to part j changes ∑knk2 by (ni−1)2+(nj+1)2−ni2−nj2=−2(ni−nj−1)<0, so it strictly increases the edge count. Repetition ends exactly when every two part sizes differ by at most 1, which forces the quotient-remainder sizes and proves both maximality and uniqueness.

step 1.1
2.2

The identity ∑i(ni−n/r)2=∑ini2−n2/r≥0 gives e≤(r−1)n2/(2r). Equality requires every ni=n/r, possible exactly when r divides n; for the balanced integer sizes the converse is immediate.

step 1.1
3.1

Steps 1.1-2.2 prove the exact count, balancing characterization, quadratic bound, and both equality cases, including n=0 and r=1.

step 1.1step 2.1step 2.2∎

Depends on

Used by

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Sources