Alphabeta Math
CorollaryStatement: AI-adaptedProof: AI-generatedSession-authored (Fable 5 assisted)precheck passaudited 2026-07-31
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  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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The complete graph on an nn-element vertex set has (n2)\binom{n}{2} edges

Statement

If VV is an nn-element set, then the complete graph KVK_V has exactly (n2)\binom n2 edges.

Facts & Assumptions

Given: A finite set VV with V=n|V|=n.

[F1]

The edge set of KVK_V is [V]2[V]^2, the set of all two-element subsets of VV (Empty and complete graphs, complete bipartite graphs, and the convention that PnP_n and CnC_n have nn vertices).

Proof

technique · direct
1.1

By [F1], E(KV)=[V]2E(K_V)=[V]^2.

F1
2.1

By [L1], [V]2=(n2)|[V]^2|=\binom n2, so step 1.1 gives E(KV)=(n2)|E(K_V)|=\binom n2.

step 1.1L1

Depends on

Used by

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 53 results over 16 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources